Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

yesy7

  • 2 years ago

Find all solutions in the interval [0, 2π). (sin x)(cos x) = 0

  • This Question is Closed
  1. yesy7
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @RolyPoly Could you help me, please? :)

  2. RolyPoly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Solve sinx = 0 or cos x = 0 The union of the solutions to the above equations is your answer.

  3. yesy7
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    So I just use the unit circle after that to find the solutions correct?

  4. yesy7
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Would they be 0, pi/2, pi, 3pi/2?

  5. RolyPoly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1389714546363:dw| So, right :)

  6. yesy7
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Thank you, you're so helpful. (:

  7. RolyPoly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Welcome!! :D

  8. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.