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RolyPoly
 11 months ago
Best ResponseYou've already chosen the best response.0\[x^{a} = \frac{1}{x^a}\]\[(xy)^m = x^my^m\]

gabriel72alv
 11 months ago
Best ResponseYou've already chosen the best response.1Please help? I still dont understand? ):

jim_thompson5910
 11 months ago
Best ResponseYou've already chosen the best response.1how far did you get gabriel72alv?

gabriel72alv
 11 months ago
Best ResponseYou've already chosen the best response.1I couldnt figure out how to put it in the equation I needed to solve it? ):

jim_thompson5910
 11 months ago
Best ResponseYou've already chosen the best response.1I'll do a similar example (just with different numbers) \[\Large \left(2w^{5}x^{8}\right)^{4}\] \[\Large \left(2\right)^{4}\left(w^{5}\right)^{4}\left(x^{8}\right)^{4}\] \[\Large \left((2)^{1}\right)^{4}\left(w^{5}\right)^{4}\left(x^{8}\right)^{4}\] \[\Large (2)^{1*4}w^{5*4}x^{8*4}\] \[\Large (2)^{4}w^{20}x^{32}\] \[\Large (2)^{4}w^{20}\frac{1}{x^{32}}\] \[\Large 16w^{20}\frac{1}{x^{32}}\] \[\Large \frac{16w^{20}}{x^{32}}\]

gabriel72alv
 11 months ago
Best ResponseYou've already chosen the best response.1So would I get (3w^3/x^6)^3 ?

jim_thompson5910
 11 months ago
Best ResponseYou've already chosen the best response.1Keep going. So far, so good.

gabriel72alv
 11 months ago
Best ResponseYou've already chosen the best response.1Theres still another step? o:

jim_thompson5910
 11 months ago
Best ResponseYou've already chosen the best response.1Yes there are more steps.

gabriel72alv
 11 months ago
Best ResponseYou've already chosen the best response.1How would you work it out to get to the next step though? I understand that.

jim_thompson5910
 11 months ago
Best ResponseYou've already chosen the best response.1You would apply the outermost exponent to each term inside

jim_thompson5910
 11 months ago
Best ResponseYou've already chosen the best response.1In other words, you would cube each piece.

gabriel72alv
 11 months ago
Best ResponseYou've already chosen the best response.1So basically would it be, (3w^3/x^6) times (3w^3/x^6) times (3w^3/x^6) ?

jim_thompson5910
 11 months ago
Best ResponseYou've already chosen the best response.1Yes pretty much

jim_thompson5910
 11 months ago
Best ResponseYou've already chosen the best response.1So that explains why, for instance, in the denominator you will have x^6*x^6*x^6 = x^(6+6+6) = x^(18)

jim_thompson5910
 11 months ago
Best ResponseYou've already chosen the best response.1A shortcut is to use this rule \[\Large (x^m)^n = x^{m*n}\]

gabriel72alv
 11 months ago
Best ResponseYou've already chosen the best response.1So would I get for my answer to that is 27w^9/x^18 ?

jim_thompson5910
 11 months ago
Best ResponseYou've already chosen the best response.1You are 100% correct. Nice work.

gabriel72alv
 11 months ago
Best ResponseYou've already chosen the best response.1Nicee! Haa, So thats my answer? xD

gabriel72alv
 11 months ago
Best ResponseYou've already chosen the best response.1Awesome, Thank you so much jim_thompson5910 ! (:

jim_thompson5910
 11 months ago
Best ResponseYou've already chosen the best response.1you're welcome
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