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anonymous
 2 years ago
(3w^3 x^6)^3
Write your answer using only positive exponents.
anonymous
 2 years ago
(3w^3 x^6)^3 Write your answer using only positive exponents.

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[x^{a} = \frac{1}{x^a}\]\[(xy)^m = x^my^m\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Please help? I still dont understand? ):

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1how far did you get gabriel72alv?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I couldnt figure out how to put it in the equation I needed to solve it? ):

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1I'll do a similar example (just with different numbers) \[\Large \left(2w^{5}x^{8}\right)^{4}\] \[\Large \left(2\right)^{4}\left(w^{5}\right)^{4}\left(x^{8}\right)^{4}\] \[\Large \left((2)^{1}\right)^{4}\left(w^{5}\right)^{4}\left(x^{8}\right)^{4}\] \[\Large (2)^{1*4}w^{5*4}x^{8*4}\] \[\Large (2)^{4}w^{20}x^{32}\] \[\Large (2)^{4}w^{20}\frac{1}{x^{32}}\] \[\Large 16w^{20}\frac{1}{x^{32}}\] \[\Large \frac{16w^{20}}{x^{32}}\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0So would I get (3w^3/x^6)^3 ?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1Keep going. So far, so good.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Theres still another step? o:

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1Yes there are more steps.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0How would you work it out to get to the next step though? I understand that.

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1You would apply the outermost exponent to each term inside

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1In other words, you would cube each piece.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0So basically would it be, (3w^3/x^6) times (3w^3/x^6) times (3w^3/x^6) ?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1Yes pretty much

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1So that explains why, for instance, in the denominator you will have x^6*x^6*x^6 = x^(6+6+6) = x^(18)

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1A shortcut is to use this rule \[\Large (x^m)^n = x^{m*n}\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0So would I get for my answer to that is 27w^9/x^18 ?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1You are 100% correct. Nice work.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Nicee! Haa, So thats my answer? xD

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Awesome, Thank you so much jim_thompson5910 ! (:

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1you're welcome
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