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Find COS 23pi/6?

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Other answers:

so I replace pi with 180?
so it'd be 23*pi divided by 6?
exactly (:
thanks :)
welcome (:
Is 12.03 Right?
cosine of a value cannot be larger than 1...
can you please explain?
See the graph of cosine:|dw:1389756073553:dw|
Maximum of a y=cos x function is 1. Minimum of a y=cosx function is -1
so do I need to graph this?
So, you cannot have COS 23pi/6 = 12.03
\[\cos\frac{23\pi}{6} = \cos(3(2\pi) + \frac{5\pi}{6}) = \cos\frac{5\pi}{6} = ...?\]
Using the attached drawing where does 23/pi fall?
Okay sir's let me tell you that. Cos23pi/6 -2pi will give you the same answer
idk where 23/pi falls
Subtract 2pi from it
The reason you don't know where it falls is becomes you have to do more than one revolution around the circle
so i subtract 2pi fom 6?
2pi = 12pi/6..So 23pi/6-12pi/6 = 11pi/6
Okay good.
Are you familiar with the unit circle in trigonometry?
Now if radians are bothering you we can convert it to degrees.
do i need like a specific calculator for this?
yes Please
You could plug this into your calculator, but if this comes up on a test and you can't use one, you will be screwed.
Can you explain how to do it manually?
That gives us 330 degrees
Do you know where that is on the unit circle?
hint: It's in quadrant IV
Okay. tell me the coordinates for it.
sqrt 2/2, -sqrt 2/2
Not quite.
That would be 315 degrees.
ummm sqrt 3/2 , -1/2
yes. sqrt(3)/2, -1/2
Okay. You should know that Cosx= x
So what is the value for Cos330?
I got -.991...
Keep this exact. You just gave me the coordinates. and I just told you CosƟ=x
so what is the exact answer?
hint: (x,y)
Use the coordinates you gave me.
sqrt 3/2 , -1/2
Yes and I told you cosƟ=x so what is cos330?
I don't get it /.\ I'm sorry
when I plug in Cos330 it gives me the decimal I gave you
Okay also cosƟ=A/H This is the unit circle and the hypotenuse will always be one so basically cosƟ=H what is Cos330?
ygarcia what calculator are you using btw?
I don't have a calculator
Okay. Well just finish it. Cos330=A. What is A in that triangle? A for adjacent to theta.
No. Adjacent means next to. So what is next to theta that isn't the hypotenuse. -1/2 is opposite.
sqrt 3/2
There you go.
so the solution is sqrt 3/2?
Now let's see if you learned anything. Tell me the sin330 if you know that sinƟ=y
Very good. Just use the coordinates you gave me for that degree value. (sqrt(3)/2, -1/2) (x,y) SinƟ=y and the y value for 330 is -1/2 so that's the answer.
So Cos= x value and Sin= y value?
In reference to the circle
Yeah. Because in the unit circle the radius is one, that's why it's called a unit circle, one unit. Anytime you have something over 1 It's just whatever the numerator is.
Okay, Thanks SO MUCH!!!! I don't fully get it yet but what you explained to me helped A LOT :)
You're welcome.

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