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Do you have a calculator?

no

π=180∘

so I replace pi with 180?

yes

so it'd be 23*pi divided by 6?

exactly (:

thanks :)

welcome (:

Is 12.03 Right?

cosine of a value cannot be larger than 1...

can you please explain?

See the graph of cosine:|dw:1389756073553:dw|

yes

Maximum of a y=cos x function is 1. Minimum of a y=cosx function is -1

so do I need to graph this?

|dw:1389756066410:dw|

So, you cannot have COS 23pi/6 = 12.03

\[\cos\frac{23\pi}{6} = \cos(3(2\pi) + \frac{5\pi}{6}) = \cos\frac{5\pi}{6} = ...?\]

Using the attached drawing where does 23/pi fall?

Okay sir's let me tell you that.
Cos23pi/6 -2pi will give you the same answer

idk where 23/pi falls

Subtract 2pi from it

so i subtract 2pi fom 6?

2pi = 12pi/6..So 23pi/6-12pi/6 = 11pi/6

Okay good.

Are you familiar with the unit circle in trigonometry?

Now if radians are bothering you we can convert it to degrees.

do i need like a specific calculator for this?

yes Please

11pi/6*180/pi

Can you explain how to do it manually?

That gives us 330 degrees

Do you know where that is on the unit circle?

hint: It's in quadrant IV

yes

Okay. tell me the coordinates for it.

sqrt 2/2, -sqrt 2/2

Not quite.

That would be 315 degrees.

ummm sqrt 3/2 , -1/2

yes. sqrt(3)/2, -1/2

Okay. You should know that Cosx= x

So what is the value for Cos330?

I got -.991...

Keep this exact. You just gave me the coordinates. and I just told you CosƟ=x

so what is the exact answer?

hint: (x,y)

Use the coordinates you gave me.

sqrt 3/2 , -1/2

Yes and I told you cosƟ=x so what is cos330?

I don't get it /.\ I'm sorry

when I plug in Cos330 it gives me the decimal I gave you

|dw:1389757103607:dw|

ygarcia what calculator are you using btw?

I don't have a calculator

Okay. Well just finish it. Cos330=A. What is A in that triangle? A for adjacent to theta.

-1/2?

|dw:1389757356882:dw|

No. Adjacent means next to. So what is next to theta that isn't the hypotenuse. -1/2 is opposite.

sqrt 3/2

There you go.

so the solution is sqrt 3/2?

cos330=Sqrt(3)/2

Yes

Now let's see if you learned anything.
Tell me the sin330 if you know that sinƟ=y

-1/2

So Cos= x value
and Sin= y value?

In reference to the circle

Okay, Thanks SO MUCH!!!! I don't fully get it yet but what you explained to me helped A LOT :)

You're welcome.