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nelsonjedi
 11 months ago
Best ResponseYou've already chosen the best response.0Do you have a calculator?

ygarcia
 11 months ago
Best ResponseYou've already chosen the best response.0so I replace pi with 180?

ygarcia
 11 months ago
Best ResponseYou've already chosen the best response.0so it'd be 23*pi divided by 6?

RolyPoly
 11 months ago
Best ResponseYou've already chosen the best response.0cosine of a value cannot be larger than 1...

ygarcia
 11 months ago
Best ResponseYou've already chosen the best response.0can you please explain?

RolyPoly
 11 months ago
Best ResponseYou've already chosen the best response.0See the graph of cosine:dw:1389756073553:dw

RolyPoly
 11 months ago
Best ResponseYou've already chosen the best response.0Maximum of a y=cos x function is 1. Minimum of a y=cosx function is 1

ygarcia
 11 months ago
Best ResponseYou've already chosen the best response.0so do I need to graph this?

nelsonjedi
 11 months ago
Best ResponseYou've already chosen the best response.0dw:1389756066410:dw

RolyPoly
 11 months ago
Best ResponseYou've already chosen the best response.0So, you cannot have COS 23pi/6 = 12.03

RolyPoly
 11 months ago
Best ResponseYou've already chosen the best response.0\[\cos\frac{23\pi}{6} = \cos(3(2\pi) + \frac{5\pi}{6}) = \cos\frac{5\pi}{6} = ...?\]

nelsonjedi
 11 months ago
Best ResponseYou've already chosen the best response.0Using the attached drawing where does 23/pi fall?

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1Okay sir's let me tell you that. Cos23pi/6 2pi will give you the same answer

ygarcia
 11 months ago
Best ResponseYou've already chosen the best response.0idk where 23/pi falls

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1The reason you don't know where it falls is becomes you have to do more than one revolution around the circle

ygarcia
 11 months ago
Best ResponseYou've already chosen the best response.0so i subtract 2pi fom 6?

nelsonjedi
 11 months ago
Best ResponseYou've already chosen the best response.02pi = 12pi/6..So 23pi/612pi/6 = 11pi/6

nelsonjedi
 11 months ago
Best ResponseYou've already chosen the best response.0Are you familiar with the unit circle in trigonometry?

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1Now if radians are bothering you we can convert it to degrees.

ygarcia
 11 months ago
Best ResponseYou've already chosen the best response.0do i need like a specific calculator for this?

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1You could plug this into your calculator, but if this comes up on a test and you can't use one, you will be screwed.

ygarcia
 11 months ago
Best ResponseYou've already chosen the best response.0Can you explain how to do it manually?

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1That gives us 330 degrees

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1Do you know where that is on the unit circle?

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1hint: It's in quadrant IV

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1Okay. tell me the coordinates for it.

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1That would be 315 degrees.

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1Okay. You should know that Cosx= x

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1So what is the value for Cos330?

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1Keep this exact. You just gave me the coordinates. and I just told you CosƟ=x

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1so what is the exact answer?

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1Use the coordinates you gave me.

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1Yes and I told you cosƟ=x so what is cos330?

ygarcia
 11 months ago
Best ResponseYou've already chosen the best response.0I don't get it /.\ I'm sorry

ygarcia
 11 months ago
Best ResponseYou've already chosen the best response.0when I plug in Cos330 it gives me the decimal I gave you

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1Okay also cosƟ=A/H This is the unit circle and the hypotenuse will always be one so basically cosƟ=H what is Cos330?

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1ygarcia what calculator are you using btw?

ygarcia
 11 months ago
Best ResponseYou've already chosen the best response.0I don't have a calculator

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1Okay. Well just finish it. Cos330=A. What is A in that triangle? A for adjacent to theta.

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1No. Adjacent means next to. So what is next to theta that isn't the hypotenuse. 1/2 is opposite.

ygarcia
 11 months ago
Best ResponseYou've already chosen the best response.0so the solution is sqrt 3/2?

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1Now let's see if you learned anything. Tell me the sin330 if you know that sinƟ=y

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1Very good. Just use the coordinates you gave me for that degree value. (sqrt(3)/2, 1/2) (x,y) SinƟ=y and the y value for 330 is 1/2 so that's the answer.

ygarcia
 11 months ago
Best ResponseYou've already chosen the best response.0So Cos= x value and Sin= y value?

ygarcia
 11 months ago
Best ResponseYou've already chosen the best response.0In reference to the circle

Lethal
 11 months ago
Best ResponseYou've already chosen the best response.1Yeah. Because in the unit circle the radius is one, that's why it's called a unit circle, one unit. Anytime you have something over 1 It's just whatever the numerator is.

ygarcia
 11 months ago
Best ResponseYou've already chosen the best response.0Okay, Thanks SO MUCH!!!! I don't fully get it yet but what you explained to me helped A LOT :)
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