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Christos
 3 years ago
Please fellow open study members, solve with me . Finals countdown 3 hours :P
https://www.dropbox.com/s/vwu945w28tgowlp/Screenshot%2020140115%2015.09.53.jpg
(ANXIETY LEVEL OVER THE TOP)
Christos
 3 years ago
Please fellow open study members, solve with me . Finals countdown 3 hours :P https://www.dropbox.com/s/vwu945w28tgowlp/Screenshot%2020140115%2015.09.53.jpg (ANXIETY LEVEL OVER THE TOP)

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hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1so where are you stuck ?

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0They are the only problems to which I don't have solutions , and I also have infinite series to cover , if you give me what I lack, it would be of a great help at the current situation ! :(

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3link is not opening for meh

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0just tell me what do I do

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0after the long division , then what

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3before we dive in, two things to keep in mind : 1) we can integrate ANY/EVERY rational function 2) to use partial fractions, degreem of numerator must always be LESS than degree of denominator

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yeah, thats the reason she did long division for 3rd

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1so, you must have something like x/x^2+1 ,right ??

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1hint : d/dx (x^2+1) = 2x

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1so take u = x^2+1 , du =...

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3for first example, since degree of numerator < degree of denominator, next do below steps : step1 : factor the denominator ive seen hartnn explaining partial fractions excellently before... so i give u hartnn :)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3@hartnn ... plz continue if u have time :)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1i have like 3 minutes :P

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3and im sure, u can make Christos understand half of calculus in less than 3 minutes ;)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1probably, if she is sitting right in front of me ;)

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0she is intenting a new study method called parallel processing !!

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1times up :P i need to rush b4 my bus leaves without me :P be back online when i reach home..

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3oh hartnn you're in office ha ... runn.. il see if i can do some justice in explaining partial fractions :)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3\(\large \frac{1}{x^2+3x4}\) factor the denominator \(\large \frac{1}{(x1)(x+4)}\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3step2 : break left fraction into sum of fractions : \(\large \frac{1}{(x1)(x+4)} = \frac{A}{x1} + \frac{B}{x+4}\) find A and B

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0answer: 1/5lnx2  1/5 lnx+4 + C

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0do I need to factor the denominator here ?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3yes, factoring IS the first step

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3and ofc, the 0th step is longdivision :)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3step1 : factor denominator \(\large \frac{1}{x(x^21)} \) \(\large \frac{1}{x(x1)(x+1)} \)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3step2 : wrote the fraction as sum of simple fractions \(\large \frac{1}{x(x1)(x+1)} = \frac{A}{x} + \frac{B}{x1} + \frac{C}{x+1}\) solve A, B, C

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3yes looks good, solve A, B, C

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0I hope you are not leading me into a teaching trap at the current moment huh :D

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3whats teaching trap lol im no teacher... guess im more toward a professor who screws his students hmm lol

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0ok I can't solve this, whats the next step :D

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0if x = 1 denominator is undefined A.k.A me missing something

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3there is a small trick to solve this, it wont take any time to learn the trick. let me show u how to find A, B, C super fast

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3\(\large \frac{1}{x(x1)(x+1)} = \frac{A}{x} + \frac{B}{x1} + \frac{C}{x+1}\) to sovle A : Multuply the whole equation wid \(x\), and plug \(x = 0\) \(\large \frac{1}{(x1)(x+1)} = A + \frac{Bx}{x1} + \frac{Cx}{x+1}\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3when u plug \(x = 0\), everything on right side cancels away, except \(A\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3\(\large \frac{1}{(01)(0+1)} = A + 0 + 0\) solve A

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3similarly find B and C

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3\(\large \frac{1}{x(x1)(x+1)} = \frac{A}{x} + \frac{B}{x1} + \frac{C}{x+1}\) to find B : multiply the whole equation wid \((x1)\) and plugin \(x = 1\) \(\large \frac{1}{x(x+1)} = \frac{A(x1)}{x} + B + \frac{C(x1)}{x+1}\)

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0and then the main fraction is undefined..

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.3\(\large \frac{1}{x(x+1)} = \frac{A(x1)}{x} + B + \frac{C(x1)}{x+1}\) plugin x = 1 \(\large \frac{1}{1(1+1)} = 0 + B + 0\)
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