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Christos
 one year ago
Please fellow open study members, solve with me . Finals countdown 3 hours :P
https://www.dropbox.com/s/vwu945w28tgowlp/Screenshot%2020140115%2015.09.53.jpg
(ANXIETY LEVEL OVER THE TOP)
Christos
 one year ago
Please fellow open study members, solve with me . Finals countdown 3 hours :P https://www.dropbox.com/s/vwu945w28tgowlp/Screenshot%2020140115%2015.09.53.jpg (ANXIETY LEVEL OVER THE TOP)

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hartnn
 one year ago
Best ResponseYou've already chosen the best response.1so where are you stuck ?

Christos
 one year ago
Best ResponseYou've already chosen the best response.0They are the only problems to which I don't have solutions , and I also have infinite series to cover , if you give me what I lack, it would be of a great help at the current situation ! :(

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3link is not opening for meh

Christos
 one year ago
Best ResponseYou've already chosen the best response.0just tell me what do I do

Christos
 one year ago
Best ResponseYou've already chosen the best response.0after the long division , then what

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3before we dive in, two things to keep in mind : 1) we can integrate ANY/EVERY rational function 2) to use partial fractions, degreem of numerator must always be LESS than degree of denominator

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1yeah, thats the reason she did long division for 3rd

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1so, you must have something like x/x^2+1 ,right ??

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1hint : d/dx (x^2+1) = 2x

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1so take u = x^2+1 , du =...

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3for first example, since degree of numerator < degree of denominator, next do below steps : step1 : factor the denominator ive seen hartnn explaining partial fractions excellently before... so i give u hartnn :)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3@hartnn ... plz continue if u have time :)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1i have like 3 minutes :P

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3and im sure, u can make Christos understand half of calculus in less than 3 minutes ;)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1probably, if she is sitting right in front of me ;)

Christos
 one year ago
Best ResponseYou've already chosen the best response.0she is intenting a new study method called parallel processing !!

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1times up :P i need to rush b4 my bus leaves without me :P be back online when i reach home..

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3oh hartnn you're in office ha ... runn.. il see if i can do some justice in explaining partial fractions :)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3\(\large \frac{1}{x^2+3x4}\) factor the denominator \(\large \frac{1}{(x1)(x+4)}\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3step2 : break left fraction into sum of fractions : \(\large \frac{1}{(x1)(x+4)} = \frac{A}{x1} + \frac{B}{x+4}\) find A and B

Christos
 one year ago
Best ResponseYou've already chosen the best response.0answer: 1/5lnx2  1/5 lnx+4 + C

Christos
 one year ago
Best ResponseYou've already chosen the best response.0do I need to factor the denominator here ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3yes, factoring IS the first step

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3and ofc, the 0th step is longdivision :)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3step1 : factor denominator \(\large \frac{1}{x(x^21)} \) \(\large \frac{1}{x(x1)(x+1)} \)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3step2 : wrote the fraction as sum of simple fractions \(\large \frac{1}{x(x1)(x+1)} = \frac{A}{x} + \frac{B}{x1} + \frac{C}{x+1}\) solve A, B, C

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3yes looks good, solve A, B, C

Christos
 one year ago
Best ResponseYou've already chosen the best response.0I hope you are not leading me into a teaching trap at the current moment huh :D

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3whats teaching trap lol im no teacher... guess im more toward a professor who screws his students hmm lol

Christos
 one year ago
Best ResponseYou've already chosen the best response.0ok I can't solve this, whats the next step :D

Christos
 one year ago
Best ResponseYou've already chosen the best response.0if x = 1 denominator is undefined A.k.A me missing something

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3there is a small trick to solve this, it wont take any time to learn the trick. let me show u how to find A, B, C super fast

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3\(\large \frac{1}{x(x1)(x+1)} = \frac{A}{x} + \frac{B}{x1} + \frac{C}{x+1}\) to sovle A : Multuply the whole equation wid \(x\), and plug \(x = 0\) \(\large \frac{1}{(x1)(x+1)} = A + \frac{Bx}{x1} + \frac{Cx}{x+1}\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3when u plug \(x = 0\), everything on right side cancels away, except \(A\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3\(\large \frac{1}{(01)(0+1)} = A + 0 + 0\) solve A

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3similarly find B and C

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3\(\large \frac{1}{x(x1)(x+1)} = \frac{A}{x} + \frac{B}{x1} + \frac{C}{x+1}\) to find B : multiply the whole equation wid \((x1)\) and plugin \(x = 1\) \(\large \frac{1}{x(x+1)} = \frac{A(x1)}{x} + B + \frac{C(x1)}{x+1}\)

Christos
 one year ago
Best ResponseYou've already chosen the best response.0and then the main fraction is undefined..

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3\(\large \frac{1}{x(x+1)} = \frac{A(x1)}{x} + B + \frac{C(x1)}{x+1}\) plugin x = 1 \(\large \frac{1}{1(1+1)} = 0 + B + 0\)
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