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Christos
Group Title
Please fellow open study members, solve with me . Finals countdown 3 hours :P https://www.dropbox.com/s/vwu945w28tgowlp/Screenshot%2020140115%2015.09.53.jpg (ANXIETY LEVEL OVER THE TOP)
 8 months ago
 8 months ago
Christos Group Title
Please fellow open study members, solve with me . Finals countdown 3 hours :P https://www.dropbox.com/s/vwu945w28tgowlp/Screenshot%2020140115%2015.09.53.jpg (ANXIETY LEVEL OVER THE TOP)
 8 months ago
 8 months ago

This Question is Closed

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so where are you stuck ?
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
They are the only problems to which I don't have solutions , and I also have infinite series to cover , if you give me what I lack, it would be of a great help at the current situation ! :(
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
link is not opening for meh
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
http://screencast.com/t/WittgfBhztpV
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
just tell me what do I do
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
for the third one
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
after the long division , then what
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
before we dive in, two things to keep in mind : 1) we can integrate ANY/EVERY rational function 2) to use partial fractions, degreem of numerator must always be LESS than degree of denominator
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
*reading carefully*
 8 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yeah, thats the reason she did long division for 3rd
 8 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so, you must have something like x/x^2+1 ,right ??
 8 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
hint : d/dx (x^2+1) = 2x
 8 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so take u = x^2+1 , du =...
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
for first example, since degree of numerator < degree of denominator, next do below steps : step1 : factor the denominator ive seen hartnn explaining partial fractions excellently before... so i give u hartnn :)
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
@hartnn ... plz continue if u have time :)
 8 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i have like 3 minutes :P
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
and im sure, u can make Christos understand half of calculus in less than 3 minutes ;)
 8 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
probably, if she is sitting right in front of me ;)
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
she is intenting a new study method called parallel processing !!
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
I am just kidding
 8 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
times up :P i need to rush b4 my bus leaves without me :P be back online when i reach home..
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
oh hartnn you're in office ha ... runn.. il see if i can do some justice in explaining partial fractions :)
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
\(\large \frac{1}{x^2+3x4}\) factor the denominator \(\large \frac{1}{(x1)(x+4)}\)
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
step2 : break left fraction into sum of fractions : \(\large \frac{1}{(x1)(x+4)} = \frac{A}{x1} + \frac{B}{x+4}\) find A and B
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
answer: 1/5lnx2  1/5 lnx+4 + C
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
thats right !
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
lets go 2nd
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
do I need to factor the denominator here ?
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
yes, factoring IS the first step
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
and ofc, the 0th step is longdivision :)
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
A/x b/x+1 C/x+1
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
B/x1 * * *
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
step1 : factor denominator \(\large \frac{1}{x(x^21)} \) \(\large \frac{1}{x(x1)(x+1)} \)
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
A B C: http://screencast.com/t/a5HayvjoOi
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
step2 : wrote the fraction as sum of simple fractions \(\large \frac{1}{x(x1)(x+1)} = \frac{A}{x} + \frac{B}{x1} + \frac{C}{x+1}\) solve A, B, C
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
yes looks good, solve A, B, C
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
I hope you are not leading me into a teaching trap at the current moment huh :D
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
ok ok I solve it now
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
whats teaching trap lol im no teacher... guess im more toward a professor who screws his students hmm lol
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
ok I can't solve this, whats the next step :D
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
if x = 1 denominator is undefined A.k.A me missing something
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
there is a small trick to solve this, it wont take any time to learn the trick. let me show u how to find A, B, C super fast
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
\(\large \frac{1}{x(x1)(x+1)} = \frac{A}{x} + \frac{B}{x1} + \frac{C}{x+1}\) to sovle A : Multuply the whole equation wid \(x\), and plug \(x = 0\) \(\large \frac{1}{(x1)(x+1)} = A + \frac{Bx}{x1} + \frac{Cx}{x+1}\)
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
when u plug \(x = 0\), everything on right side cancels away, except \(A\)
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
\(\large \frac{1}{(01)(0+1)} = A + 0 + 0\) solve A
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
yes, A = 1
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
similarly find B and C
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
\(\large \frac{1}{x(x1)(x+1)} = \frac{A}{x} + \frac{B}{x1} + \frac{C}{x+1}\) to find B : multiply the whole equation wid \((x1)\) and plugin \(x = 1\) \(\large \frac{1}{x(x+1)} = \frac{A(x1)}{x} + B + \frac{C(x1)}{x+1}\)
 8 months ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
and then the main fraction is undefined..
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
\(\large \frac{1}{x(x+1)} = \frac{A(x1)}{x} + B + \frac{C(x1)}{x+1}\) plugin x = 1 \(\large \frac{1}{1(1+1)} = 0 + B + 0\)
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
il let u solve C :)
 8 months ago
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