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DontLikeMathButOhWell
 11 months ago
Best ResponseYou've already chosen the best response.0Steps to solve 12 + x Less than equal to 2x  2

whpalmer4
 11 months ago
Best ResponseYou've already chosen the best response.2\[12+x \le 2x2\]We want to rearrange the inequality so that \(x\) appears by itself on one side of the inequality sign, with everything else on the other. I would suggest that perhaps subtracting \(x\) from both sides would be a good way to start.

whpalmer4
 11 months ago
Best ResponseYou've already chosen the best response.2\[12+x\le2x2\]\[12+xx\le2x2x\]\[12\le x2\]Now what?

DontLikeMathButOhWell
 11 months ago
Best ResponseYou've already chosen the best response.0Subtract 2?

whpalmer4
 11 months ago
Best ResponseYou've already chosen the best response.2Add 2 to both sides, to get rid of the 2 on the side with the x

whpalmer4
 11 months ago
Best ResponseYou've already chosen the best response.2\[12+2\le x2+2\]\[14 \le x\]

whpalmer4
 11 months ago
Best ResponseYou've already chosen the best response.2or subtract 2 from both sides would work, too, but that's probably more errorprone for most people

DontLikeMathButOhWell
 11 months ago
Best ResponseYou've already chosen the best response.0why would you add 2?

DontLikeMathButOhWell
 11 months ago
Best ResponseYou've already chosen the best response.0Ohh okay thanks alot.

whpalmer4
 11 months ago
Best ResponseYou've already chosen the best response.2because \[2 + 2 = 0\]

DontLikeMathButOhWell
 11 months ago
Best ResponseYou've already chosen the best response.0Okay thank you @whpalmer4
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