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One way to write Coulomb's law is F=(k lQql)/(r^2) where F is the magnitude of the electric force, k is a constant, Q and q are the two electrical charges and r is the distance between them. Solve Coulomb's law for r.
 3 months ago
 3 months ago
One way to write Coulomb's law is F=(k lQql)/(r^2) where F is the magnitude of the electric force, k is a constant, Q and q are the two electrical charges and r is the distance between them. Solve Coulomb's law for r.
 3 months ago
 3 months ago

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douglaswinslowcooperBest ResponseYou've already chosen the best response.1
Multiply both sides by r^2, to get it on the left. Divide both by F, to get it on the right. r^2 = etc. r = sqrt(etc.) you should finish it.
 3 months ago

BaoZhuBest ResponseYou've already chosen the best response.0
i did it, and it gave me r=+,(sqrt(k(Qq))/(sqrt(F)), however, the system still reads it as incorrect, is there i'm missing with the absolute value of “Qq”？
 3 months ago

douglaswinslowcooperBest ResponseYou've already chosen the best response.1
r cannot be negative as it is a distance. Did you use Qq or (Qq)? Former is needed.
 3 months ago

BaoZhuBest ResponseYou've already chosen the best response.0
i can not use capital Q, because wileyplus(the software) do not allow me to.
 3 months ago

douglaswinslowcooperBest ResponseYou've already chosen the best response.1
You have the right formula for the answer.
 3 months ago

BaoZhuBest ResponseYou've already chosen the best response.0
so, it's the system itself that is not accepting the answer?and not that my answer is incorrect?
 3 months ago

RaphaelFilgueirasBest ResponseYou've already chosen the best response.0
you forget the modulus inside sqrt
 3 months ago

BaoZhuBest ResponseYou've already chosen the best response.0
so there it should be absolute value of q1q2?
 3 months ago

RaphaelFilgueirasBest ResponseYou've already chosen the best response.0
yes , imagine ,if the value of product were negative will give you an complex radius
 3 months ago

BaoZhuBest ResponseYou've already chosen the best response.0
will that be the answer? sorry about all the questions, i don't want to submit the answer before it is right since i only have 1 more attempt left.
 3 months ago
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