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BaoZhu
 one year ago
One way to write Coulomb's law is F=(k lQql)/(r^2) where F is the magnitude of the electric force, k is a constant, Q and q are the two electrical charges and r is the distance between them. Solve Coulomb's law for r.
BaoZhu
 one year ago
One way to write Coulomb's law is F=(k lQql)/(r^2) where F is the magnitude of the electric force, k is a constant, Q and q are the two electrical charges and r is the distance between them. Solve Coulomb's law for r.

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douglaswinslowcooper
 one year ago
Best ResponseYou've already chosen the best response.1Multiply both sides by r^2, to get it on the left. Divide both by F, to get it on the right. r^2 = etc. r = sqrt(etc.) you should finish it.

BaoZhu
 one year ago
Best ResponseYou've already chosen the best response.0i did it, and it gave me r=+,(sqrt(k(Qq))/(sqrt(F)), however, the system still reads it as incorrect, is there i'm missing with the absolute value of “Qq”？

douglaswinslowcooper
 one year ago
Best ResponseYou've already chosen the best response.1r cannot be negative as it is a distance. Did you use Qq or (Qq)? Former is needed.

BaoZhu
 one year ago
Best ResponseYou've already chosen the best response.0i can not use capital Q, because wileyplus(the software) do not allow me to.

douglaswinslowcooper
 one year ago
Best ResponseYou've already chosen the best response.1You have the right formula for the answer.

BaoZhu
 one year ago
Best ResponseYou've already chosen the best response.0so, it's the system itself that is not accepting the answer?and not that my answer is incorrect?

RaphaelFilgueiras
 one year ago
Best ResponseYou've already chosen the best response.0you forget the modulus inside sqrt

BaoZhu
 one year ago
Best ResponseYou've already chosen the best response.0so there it should be absolute value of q1q2?

RaphaelFilgueiras
 one year ago
Best ResponseYou've already chosen the best response.0yes , imagine ,if the value of product were negative will give you an complex radius

BaoZhu
 one year ago
Best ResponseYou've already chosen the best response.0will that be the answer? sorry about all the questions, i don't want to submit the answer before it is right since i only have 1 more attempt left.
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