A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Hey all! In the following problem I need to draw the freebody diagram of the cylinder an determine the magnitudes of AC and CD:
The hydraulic cylinder is subjected to three forces. An 8 kN force is exerted on the cylinder at B that is parallel to the cylinder and points from B toward C. The link AC exerts a force at C that is parallel to the line from A to C. The link CD exerts a force at C that is parallel to the line from C to D. I'll include the image in the comments.
anonymous
 3 years ago
Hey all! In the following problem I need to draw the freebody diagram of the cylinder an determine the magnitudes of AC and CD: The hydraulic cylinder is subjected to three forces. An 8 kN force is exerted on the cylinder at B that is parallel to the cylinder and points from B toward C. The link AC exerts a force at C that is parallel to the line from A to C. The link CD exerts a force at C that is parallel to the line from C to D. I'll include the image in the comments.

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Here is a rough sketch of the problem, with included dimensions.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I need the free body diagram. I can figure it out from there.

LastDayWork
 3 years ago
Best ResponseYou've already chosen the best response.1Attempt to draw it yourself first; and I'll correct it :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok here is what I got, but it makes no sense to me. There must be normal forces somewhere but I'm not sure where to put them:

LastDayWork
 3 years ago
Best ResponseYou've already chosen the best response.1I think the three forces are themselves normal forces (or tension; whatever you are used to call them).

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wait wha........but i'm still missing forces in order to balance aren't I? as it is now point C should be moving upward. There must be some force keeping it down right?

LastDayWork
 3 years ago
Best ResponseYou've already chosen the best response.1Honestly, I don't know how this arrangement will work (or what purpose it is used for). As we are using rods (instead of strings), the tension will change its direction from compressional to extensional (or viceversa) to keep the point C in equilibrium.

LastDayWork
 3 years ago
Best ResponseYou've already chosen the best response.1Consider posting the original question.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0This question is coming out of my textbook so I'm not sure how to get it from the page to here.

LastDayWork
 3 years ago
Best ResponseYou've already chosen the best response.1If you have a camera, upload the image.

LastDayWork
 3 years ago
Best ResponseYou've already chosen the best response.1@VincentLyon.Fr @douglaswinslowcooper @Garm

LastDayWork
 3 years ago
Best ResponseYou've already chosen the best response.1Took some time, but I think I understand it now. (Note that the arrows indicate force vectors.) Try to find how I chose between compressional and extensional tension? Also, find where does Fex comes from?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok yeah I'm looking at it now. I understand where everything is coming from except the Fex. the problem doesn't say anything about an external force being applied...

LastDayWork
 3 years ago
Best ResponseYou've already chosen the best response.1It's not an external force; take a closer look at the diagram.

LastDayWork
 3 years ago
Best ResponseYou've already chosen the best response.1I used the term Fex in the same sense as "...Cats are liquid" :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok let me see if I understand the diagram: the forces in each of the rods causes a reaction force at the other points. The liquid in the cylinder is compressed causing a reaction force from the liquid?

LastDayWork
 3 years ago
Best ResponseYou've already chosen the best response.1There is also a string attached to the hydraulic cylinder. The hydraulic part only involves the fact that we can convert a weaker force into a stronger one; simply by changing the area on which the force is applied.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0OHHH so the tension in the string pulling backwards is what is causing Fex? and it's equal and opposite to the 8000 N force?

LastDayWork
 3 years ago
Best ResponseYou've already chosen the best response.1For more on hydraulics; read  http://en.wikipedia.org/wiki/Hydraulic_drive_system. "...OHHH so the tension in the string pulling backwards is what is causing Fex?..." Yes "...it's equal and opposite to the 8000 N force?..." You can do the (vector) addition yourself as I am a very lazy guy :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok awesome this actually makes sense now. just needed to figure that out.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Could you take a look at one quick question?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0http://openstudy.com/study#/updates/52db802ee4b003c643a003f5
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.