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anonymous
 2 years ago
Hey I need help figuring out the free body diagram for a block and tackle system. Problem will be in the comments.
anonymous
 2 years ago
Hey I need help figuring out the free body diagram for a block and tackle system. Problem will be in the comments.

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I've worked with pulley systems before, but I'm not sure how to go about this one.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0take the boy as the system....forces acting on him are 1) tension by rope 2) normal force exerted by the beam he is sitting on

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0+ 3) the weight of the boy downwards

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0So the whole pully system doesn't affect the problem? I'm sure it does...

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0can u explain what u meant?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry I'm really bad at explaining myself. In order to determine the force he's exerting we need to figure out how much force is required by this pulley system to lift 120 lbs right?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0So perhaps the question is rather what are all the relevant free body diagrams in this problem.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0since it moves at a constant velocity, i guess the force exerted by him = tension in the rope

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0and u are right,this is all about taking free body diagrams and finding unknowns

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0So how can I take the free body diagrams at the pulleys? the boy's is relatively simple as you mentioned.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0as long as the pulley is massless, u neednt take it into consideration

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I mean the whole mess of ropes around the pulleys

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0next you can take the beam as the free body, and the forces acting on it,,,1) normal force from the boy downwards, 2) weight downwards 3) tension upwards,,,,,equate to zero

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0the tension in the rope goes around the top pulley so the tension in the rope from the top to the bottom pulley is the same as the tension in the rope....does the tackle system provide a mechanical advantage of 2?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0or is it an advantage of 4 since the rope goes around the bottom pulley twice?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0the pulley thing is rather complex,,,i guess the advantage is 4,,,perhaps @LastDayWork may help u better,,,expert at physics

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@LastDayWork is it 4? It would seem so looking at the picture, since the weight of the boy/beam system is 120lb, the boy only needs to pull with 1/4 of the force since 4 ropes are supporting that weight no?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Is there something below the diagram; because I can't clearly makeout how the rope is attached to the beam (in which the boy is sitting).

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0No. but I don't think it matters, since they just say the system and ignore the angle at which the rope is.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Assuming that the tension in the hook in the bottom is 120lbs, and the tension in the other rope is whatever pull the boy is applying, wouldn't the pull be a quarter of the weight? not sure.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I am not considering the angle; its just that the tone of the question implies that the boy is lifting the beam along with himself (hence the combined weight).

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0^^ But I cant see how

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0yeah, but doesn't that mean we can pretend the boy/bar system is just a box of weight 120lb? I think the bar slides up the vertical column, but that doesn't affect the problem.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0A box climbing a rope ?? :P

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Well I have seen physics problems that say to work with perfectly spherical elephants whose mass can be ignored soo....why not?

JoannaBlackwelder
 2 years ago
Best ResponseYou've already chosen the best response.0It looks like to me that the problem states that 120 lbs is the combined weight.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0exactly. from the picture we need to determine the force exerted by the boy. I'm thinking that the tackle system provides a mechanical advantage of4 but i'm not sure.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Since the weight is supported by 4 ropes that lead to the top pulley, and the rope the boy is pulling on is equal to one of these ropes, then the force he uses to pull is a quarter of the weight right? or do I have faulty reasoning?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0As far as I can understand  There is some sort of spring attached to the hook of upper pulley (above the picture). By pulling the rope, the boy decreases the distance between the pulleys; and as the lower pulley can't move the (hypothetical) spring will get stretched to account for the displacement of upper pulley. There is a slag in the rope below the point where the boy is holding it (implies no tension). So the question is how is the boy lifting himself??

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Ok this is getting ridiculously complicated. This shouldn't be that convoluted....

wolfe8
 2 years ago
Best ResponseYou've already chosen the best response.0Wouldn't it be the same as the weight of him and the beam? (Is he lifting the beam up as well?)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0yeah he is. However, the force he's using isn't equal to the weight of the system. The pulleys provide mechanical advantage. I just looked up a double block and tackle system and yeah the advantage is 4, so I guess he pulls with a force of 30 lbs.

wolfe8
 2 years ago
Best ResponseYou've already chosen the best response.0The pulley just allows complete transfer of force though. Since we assume the weight of the pulley is negligible, it does not contribute to the force through torque as a pulley with mass would.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0exactly. Well I think I have my answer. Thanks everyone for taking the time to break your heads on this one.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0It's not a simple pulley. It's a double tackle

wolfe8
 2 years ago
Best ResponseYou've already chosen the best response.0Whoah. Didn't notice that. That's what happens when you jump into a question. Well good luck. Sorry I couldn't help more.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0a single pulley would transfer, so he would pull with the same force as the combined weight. If it were a single block and tackle, the rope would loop once around the bottom ,providing a mechanical advantage of 2, etc. Thanks anyways Wolfe :)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0good night everyone! Thanks.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0If somebody else were pulling the rope and not the boy himself, I would divide the total weight by 4, as there are 4 ropes supporting him. But as the boy is pulling the rope himself, there is a 5th tension acting on him, so I would divide the total weight by 5.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@VincentLyon.Fr How can the boy pull himself (along with the beam) ??

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Well, I understand he is holding and pulling the rope with his hands.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0That way he can pull himself but not the beam (why would question give us combined weight).
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