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Sorry I'm really bad at explaining myself. In order to determine the force he's exerting we need to figure out how much force is required by this pulley system to lift 120 lbs right?
next you can take the beam as the free body, and the forces acting on it,,,1) normal force from the boy downwards, 2) weight downwards 3) tension upwards,,,,,equate to zero
the tension in the rope goes around the top pulley so the tension in the rope from the top to the bottom pulley is the same as the tension in the rope....does the tackle system provide a mechanical advantage of 2?
@LastDayWork is it 4? It would seem so looking at the picture, since the weight of the boy/beam system is 120lb, the boy only needs to pull with 1/4 of the force since 4 ropes are supporting that weight no?
Assuming that the tension in the hook in the bottom is 120lbs, and the tension in the other rope is whatever pull the boy is applying, wouldn't the pull be a quarter of the weight? not sure.
I am not considering the angle; its just that the tone of the question implies that the boy is lifting the beam along with himself (hence the combined weight).
yeah, but doesn't that mean we can pretend the boy/bar system is just a box of weight 120lb? I think the bar slides up the vertical column, but that doesn't affect the problem.
exactly. from the picture we need to determine the force exerted by the boy. I'm thinking that the tackle system provides a mechanical advantage of4 but i'm not sure.
Since the weight is supported by 4 ropes that lead to the top pulley, and the rope the boy is pulling on is equal to one of these ropes, then the force he uses to pull is a quarter of the weight right? or do I have faulty reasoning?
As far as I can understand -
There is some sort of spring attached to the hook of upper pulley (above the picture).
By pulling the rope, the boy decreases the distance between the pulleys; and as the lower pulley can't move the (hypothetical) spring will get stretched to account for the displacement of upper pulley.
There is a slag in the rope below the point where the boy is holding it (implies no tension).
So the question is how is the boy lifting himself??
yeah he is. However, the force he's using isn't equal to the weight of the system. The pulleys provide mechanical advantage. I just looked up a double block and tackle system and yeah the advantage is 4, so I guess he pulls with a force of 30 lbs.
The pulley just allows complete transfer of force though. Since we assume the weight of the pulley is negligible, it does not contribute to the force through torque as a pulley with mass would.
a single pulley would transfer, so he would pull with the same force as the combined weight. If it were a single block and tackle, the rope would loop once around the bottom ,providing a mechanical advantage of 2, etc. Thanks anyways Wolfe :)
If somebody else were pulling the rope and not the boy himself, I would divide the total weight by 4, as there are 4 ropes supporting him.
But as the boy is pulling the rope himself, there is a 5th tension acting on him, so I would divide the total weight by 5.