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calculusxy

  • 2 years ago

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  1. calculusxy
    • 2 years ago
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  2. calculusxy
    • 2 years ago
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    Can you explain?

  3. calculusxy
    • 2 years ago
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    I will try my best to understand if only you can post your method. I wish to understand on how I can solve this problem.

  4. calculusxy
    • 2 years ago
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    @ganeshie8

  5. calculusxy
    • 2 years ago
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    @hartnn

  6. amoodarya
    • 2 years ago
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    after 20 min a--->2a after 20 min 2a--->4a so after4 hours = 4*3 (20min) \[a \times 2^{12}=4096 a\]

  7. hartnn
    • 2 years ago
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    "each" microbes means A =1 so u just need 'n' now how many '20 minutes' interval are there in 4 hrs ?

  8. hartnn
    • 2 years ago
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    "population of only one microbe" thats why A=1

  9. calculusxy
    • 2 years ago
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    The difficulty that I have is when it says about A being the initial size of the population. What does that mean?

  10. hartnn
    • 2 years ago
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    initial population means how many microbes are taken into consideration before reproduction process starts

  11. calculusxy
    • 2 years ago
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    So what would I put for A?

  12. hartnn
    • 2 years ago
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    "population of only one microbe" thats why A=1

  13. calculusxy
    • 2 years ago
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    Doesn't this have a repetition of like 12 more times then? Or something else?

  14. hartnn
    • 2 years ago
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    in 4 hours? since they reproduce every 20 minutes, in 4 hours, they will reproduce 12 times. thats why n=12 now you have everything you need to use the formula given.

  15. calculusxy
    • 2 years ago
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    Yes I was talking for 4 hours. Anyway, will the formula be like: \[P=12 \times 2^{12}\] @hartnn

  16. hartnn
    • 2 years ago
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    A =1, not 12

  17. calculusxy
    • 2 years ago
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    Okay. Makes more sense now. This is because the first size was 1 right? But would the new formula be like: \[P= 1 \times 2^{12}\]

  18. calculusxy
    • 2 years ago
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    Which \[P=4096\]

  19. hartnn
    • 2 years ago
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    yes, correct. initial means only at the beginning, not at every interval ...

  20. calculusxy
    • 2 years ago
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    Thank you @hartnn . You are a really good teacher. If I need more help, may I ask you?

  21. hartnn
    • 2 years ago
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    sure, no problem :) welcome ^_^

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