## calculusxy Group Title MEDAL 7 months ago 7 months ago

1. calculusxy Group Title

2. calculusxy Group Title

Can you explain?

3. calculusxy Group Title

I will try my best to understand if only you can post your method. I wish to understand on how I can solve this problem.

4. calculusxy Group Title

@ganeshie8

5. calculusxy Group Title

@hartnn

6. amoodarya Group Title

after 20 min a--->2a after 20 min 2a--->4a so after4 hours = 4*3 (20min) $a \times 2^{12}=4096 a$

7. hartnn Group Title

"each" microbes means A =1 so u just need 'n' now how many '20 minutes' interval are there in 4 hrs ?

8. hartnn Group Title

"population of only one microbe" thats why A=1

9. calculusxy Group Title

The difficulty that I have is when it says about A being the initial size of the population. What does that mean?

10. hartnn Group Title

initial population means how many microbes are taken into consideration before reproduction process starts

11. calculusxy Group Title

So what would I put for A?

12. hartnn Group Title

"population of only one microbe" thats why A=1

13. calculusxy Group Title

Doesn't this have a repetition of like 12 more times then? Or something else?

14. hartnn Group Title

in 4 hours? since they reproduce every 20 minutes, in 4 hours, they will reproduce 12 times. thats why n=12 now you have everything you need to use the formula given.

15. calculusxy Group Title

Yes I was talking for 4 hours. Anyway, will the formula be like: $P=12 \times 2^{12}$ @hartnn

16. hartnn Group Title

A =1, not 12

17. calculusxy Group Title

Okay. Makes more sense now. This is because the first size was 1 right? But would the new formula be like: $P= 1 \times 2^{12}$

18. calculusxy Group Title

Which $P=4096$

19. hartnn Group Title

yes, correct. initial means only at the beginning, not at every interval ...

20. calculusxy Group Title

Thank you @hartnn . You are a really good teacher. If I need more help, may I ask you?

21. hartnn Group Title

sure, no problem :) welcome ^_^