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calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1I will try my best to understand if only you can post your method. I wish to understand on how I can solve this problem.

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.0after 20 min a>2a after 20 min 2a>4a so after4 hours = 4*3 (20min) \[a \times 2^{12}=4096 a\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1"each" microbes means A =1 so u just need 'n' now how many '20 minutes' interval are there in 4 hrs ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1"population of only one microbe" thats why A=1

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1The difficulty that I have is when it says about A being the initial size of the population. What does that mean?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1initial population means how many microbes are taken into consideration before reproduction process starts

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1So what would I put for A?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1"population of only one microbe" thats why A=1

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1Doesn't this have a repetition of like 12 more times then? Or something else?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1in 4 hours? since they reproduce every 20 minutes, in 4 hours, they will reproduce 12 times. thats why n=12 now you have everything you need to use the formula given.

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1Yes I was talking for 4 hours. Anyway, will the formula be like: \[P=12 \times 2^{12}\] @hartnn

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1Okay. Makes more sense now. This is because the first size was 1 right? But would the new formula be like: \[P= 1 \times 2^{12}\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1yes, correct. initial means only at the beginning, not at every interval ...

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1Thank you @hartnn . You are a really good teacher. If I need more help, may I ask you?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1sure, no problem :) welcome ^_^
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