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calculusxy
 3 years ago
MEDAL
calculusxy
 3 years ago
MEDAL

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calculusxy
 3 years ago
Best ResponseYou've already chosen the best response.1I will try my best to understand if only you can post your method. I wish to understand on how I can solve this problem.

amoodarya
 3 years ago
Best ResponseYou've already chosen the best response.0after 20 min a>2a after 20 min 2a>4a so after4 hours = 4*3 (20min) \[a \times 2^{12}=4096 a\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1"each" microbes means A =1 so u just need 'n' now how many '20 minutes' interval are there in 4 hrs ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1"population of only one microbe" thats why A=1

calculusxy
 3 years ago
Best ResponseYou've already chosen the best response.1The difficulty that I have is when it says about A being the initial size of the population. What does that mean?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1initial population means how many microbes are taken into consideration before reproduction process starts

calculusxy
 3 years ago
Best ResponseYou've already chosen the best response.1So what would I put for A?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1"population of only one microbe" thats why A=1

calculusxy
 3 years ago
Best ResponseYou've already chosen the best response.1Doesn't this have a repetition of like 12 more times then? Or something else?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1in 4 hours? since they reproduce every 20 minutes, in 4 hours, they will reproduce 12 times. thats why n=12 now you have everything you need to use the formula given.

calculusxy
 3 years ago
Best ResponseYou've already chosen the best response.1Yes I was talking for 4 hours. Anyway, will the formula be like: \[P=12 \times 2^{12}\] @hartnn

calculusxy
 3 years ago
Best ResponseYou've already chosen the best response.1Okay. Makes more sense now. This is because the first size was 1 right? But would the new formula be like: \[P= 1 \times 2^{12}\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yes, correct. initial means only at the beginning, not at every interval ...

calculusxy
 3 years ago
Best ResponseYou've already chosen the best response.1Thank you @hartnn . You are a really good teacher. If I need more help, may I ask you?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1sure, no problem :) welcome ^_^
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