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calculusxy Group Title

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  • 10 months ago
  • 10 months ago

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  1. calculusxy Group Title
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    • 10 months ago
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  2. calculusxy Group Title
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    Can you explain?

    • 10 months ago
  3. calculusxy Group Title
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    I will try my best to understand if only you can post your method. I wish to understand on how I can solve this problem.

    • 10 months ago
  4. calculusxy Group Title
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    @ganeshie8

    • 10 months ago
  5. calculusxy Group Title
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    @hartnn

    • 10 months ago
  6. amoodarya Group Title
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    after 20 min a--->2a after 20 min 2a--->4a so after4 hours = 4*3 (20min) \[a \times 2^{12}=4096 a\]

    • 10 months ago
  7. hartnn Group Title
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    "each" microbes means A =1 so u just need 'n' now how many '20 minutes' interval are there in 4 hrs ?

    • 10 months ago
  8. hartnn Group Title
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    "population of only one microbe" thats why A=1

    • 10 months ago
  9. calculusxy Group Title
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    The difficulty that I have is when it says about A being the initial size of the population. What does that mean?

    • 10 months ago
  10. hartnn Group Title
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    initial population means how many microbes are taken into consideration before reproduction process starts

    • 10 months ago
  11. calculusxy Group Title
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    So what would I put for A?

    • 10 months ago
  12. hartnn Group Title
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    "population of only one microbe" thats why A=1

    • 10 months ago
  13. calculusxy Group Title
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    Doesn't this have a repetition of like 12 more times then? Or something else?

    • 10 months ago
  14. hartnn Group Title
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    in 4 hours? since they reproduce every 20 minutes, in 4 hours, they will reproduce 12 times. thats why n=12 now you have everything you need to use the formula given.

    • 10 months ago
  15. calculusxy Group Title
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    Yes I was talking for 4 hours. Anyway, will the formula be like: \[P=12 \times 2^{12}\] @hartnn

    • 10 months ago
  16. hartnn Group Title
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    A =1, not 12

    • 10 months ago
  17. calculusxy Group Title
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    Okay. Makes more sense now. This is because the first size was 1 right? But would the new formula be like: \[P= 1 \times 2^{12}\]

    • 10 months ago
  18. calculusxy Group Title
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    Which \[P=4096\]

    • 10 months ago
  19. hartnn Group Title
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    yes, correct. initial means only at the beginning, not at every interval ...

    • 10 months ago
  20. calculusxy Group Title
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    Thank you @hartnn . You are a really good teacher. If I need more help, may I ask you?

    • 10 months ago
  21. hartnn Group Title
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    sure, no problem :) welcome ^_^

    • 10 months ago
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