## OpenSessame Group Title Ammonia, NH3, is produced through a combination reaction involving N2(g) and H2(g). If 24.0 mol of H2(g) react with excess N2(g), how many moles of ammonia are produced? 7 months ago 7 months ago

1. OpenSessame Group Title

I need to know how to solve this, I'm a bit rusty on my moles.

2. wolfe8 Group Title

First, make sure the equation is balanced. Next, can you find the number of moles of whatever substance you have? Use this: http://www.ptable.com/

3. wolfe8 Group Title

I mean, write a balanced equation first.

4. OpenSessame Group Title

So..$N _{2}(g) + h _{2}(g) \rightarrow NH _{3}$

5. OpenSessame Group Title

Is that the right equation?

6. OpenSessame Group Title

$N _{2}+3H _{2} \rightarrow 2NH _{3}$

7. wolfe8 Group Title

Oh my the equation editor is not working for me but I can see it. From here can you just use normal typing? Notice that the equation is not balanced. You have 2 N on the left and one on the right. And you have 2 H on the left and 3 on the right.

8. OpenSessame Group Title

so N2 + 3H2 = 2NH3

9. wolfe8 Group Title

Right. So now, you know how much H2 you used. Can you fine the number of moles of it? http://erhs.rcsnc.org/UserFiles/Servers/Server_4766394/Image/Donna%20Scofield/mole%20conversion%20map.bmp

10. OpenSessame Group Title

Uh...Walk me through?

11. wolfe8 Group Title

Sure. Do you know how to find the number of moles?

12. OpenSessame Group Title

I know a mole is 6.02 * 10^23 thats about it

13. wolfe8 Group Title

That is the Avogadro number - the number of objects in 1 mole of substance. But I'm sorry I misread the question. You are already given the number of moles. So here, from our balanced equation N2 + 3H2 = 2NH3 we can see that 3 parts of H2 produces 2 parts of NH3. What do you think we will do to get the moles of NH3?

14. OpenSessame Group Title

Theres some formuala...

15. wolfe8 Group Title

Nah. You have 24 mol which equals to 3 parts. Find for one part and multiple by 2 to get the mols of NH3

16. OpenSessame Group Title

Uhm...One part meaning?

17. wolfe8 Group Title

One proportion by ratio

18. OpenSessame Group Title

Can you show me, I feel so lost...

19. wolfe8 Group Title

Sure. So 24 mol is equal to 3 parts of H2 we use based on the equation so we divide 24 by 3. Then we know we get 2 parts of NH3 from the equation so we multiply it by 2

20. wolfe8 Group Title

24/3*2 Get it? Want me to show it where there's whiteboard and mic?

21. OpenSessame Group Title

Yeah!

22. OpenSessame Group Title

so would it be 4 as the final answer?

23. wolfe8 Group Title

Yeah. 4 mols. Do you understand what we did though?

24. wolfe8 Group Title

NOOOOOO. 24/3 is 8 multiplied by 2 is 16

25. OpenSessame Group Title

You know there is 24 mol. In 3 equal parts oh H2 and 2 equal parts of NH3?

26. OpenSessame Group Title

Where do you get that information though? and oh okay just error in what comes first! sorry

27. wolfe8 Group Title

Right. This is why we always need the balanced equation for stoichiometry.

28. OpenSessame Group Title

Can you show me on the whiteboard?

29. wolfe8 Group Title

Sure. Can you make a meeting on twiddla.com ? I can't because I already made one. Sent the link to me in PM

30. OpenSessame Group Title

Actually its okay! i think i understood! Thanks so much for the help

31. wolfe8 Group Title

Alright good job. Have a good night