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OpenSessame

  • 11 months ago

Ammonia, NH3, is produced through a combination reaction involving N2(g) and H2(g). If 24.0 mol of H2(g) react with excess N2(g), how many moles of ammonia are produced?

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  1. OpenSessame
    • 11 months ago
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    I need to know how to solve this, I'm a bit rusty on my moles.

  2. wolfe8
    • 11 months ago
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    First, make sure the equation is balanced. Next, can you find the number of moles of whatever substance you have? Use this: http://www.ptable.com/

  3. wolfe8
    • 11 months ago
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    I mean, write a balanced equation first.

  4. OpenSessame
    • 11 months ago
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    So..\[N _{2}(g) + h _{2}(g) \rightarrow NH _{3}\]

  5. OpenSessame
    • 11 months ago
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    Is that the right equation?

  6. OpenSessame
    • 11 months ago
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    \[N _{2}+3H _{2} \rightarrow 2NH _{3}\]

  7. wolfe8
    • 11 months ago
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    Oh my the equation editor is not working for me but I can see it. From here can you just use normal typing? Notice that the equation is not balanced. You have 2 N on the left and one on the right. And you have 2 H on the left and 3 on the right.

  8. OpenSessame
    • 11 months ago
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    so N2 + 3H2 = 2NH3

  9. wolfe8
    • 11 months ago
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    Right. So now, you know how much H2 you used. Can you fine the number of moles of it? http://erhs.rcsnc.org/UserFiles/Servers/Server_4766394/Image/Donna%20Scofield/mole%20conversion%20map.bmp

  10. OpenSessame
    • 11 months ago
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    Uh...Walk me through?

  11. wolfe8
    • 11 months ago
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    Sure. Do you know how to find the number of moles?

  12. OpenSessame
    • 11 months ago
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    I know a mole is 6.02 * 10^23 thats about it

  13. wolfe8
    • 11 months ago
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    That is the Avogadro number - the number of objects in 1 mole of substance. But I'm sorry I misread the question. You are already given the number of moles. So here, from our balanced equation N2 + 3H2 = 2NH3 we can see that 3 parts of H2 produces 2 parts of NH3. What do you think we will do to get the moles of NH3?

  14. OpenSessame
    • 11 months ago
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    Theres some formuala...

  15. wolfe8
    • 11 months ago
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    Nah. You have 24 mol which equals to 3 parts. Find for one part and multiple by 2 to get the mols of NH3

  16. OpenSessame
    • 11 months ago
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    Uhm...One part meaning?

  17. wolfe8
    • 11 months ago
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    One proportion by ratio

  18. OpenSessame
    • 11 months ago
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    Can you show me, I feel so lost...

  19. wolfe8
    • 11 months ago
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    Sure. So 24 mol is equal to 3 parts of H2 we use based on the equation so we divide 24 by 3. Then we know we get 2 parts of NH3 from the equation so we multiply it by 2

  20. wolfe8
    • 11 months ago
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    24/3*2 Get it? Want me to show it where there's whiteboard and mic?

  21. OpenSessame
    • 11 months ago
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    Yeah!

  22. OpenSessame
    • 11 months ago
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    so would it be 4 as the final answer?

  23. wolfe8
    • 11 months ago
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    Yeah. 4 mols. Do you understand what we did though?

  24. wolfe8
    • 11 months ago
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    NOOOOOO. 24/3 is 8 multiplied by 2 is 16

  25. OpenSessame
    • 11 months ago
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    You know there is 24 mol. In 3 equal parts oh H2 and 2 equal parts of NH3?

  26. OpenSessame
    • 11 months ago
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    Where do you get that information though? and oh okay just error in what comes first! sorry

  27. wolfe8
    • 11 months ago
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    Right. This is why we always need the balanced equation for stoichiometry.

  28. OpenSessame
    • 11 months ago
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    Can you show me on the whiteboard?

  29. wolfe8
    • 11 months ago
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    Sure. Can you make a meeting on twiddla.com ? I can't because I already made one. Sent the link to me in PM

  30. OpenSessame
    • 11 months ago
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    Actually its okay! i think i understood! Thanks so much for the help

  31. wolfe8
    • 11 months ago
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    Alright good job. Have a good night

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