anonymous
  • anonymous
Ammonia, NH3, is produced through a combination reaction involving N2(g) and H2(g). If 24.0 mol of H2(g) react with excess N2(g), how many moles of ammonia are produced?
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
I need to know how to solve this, I'm a bit rusty on my moles.
wolfe8
  • wolfe8
First, make sure the equation is balanced. Next, can you find the number of moles of whatever substance you have? Use this: http://www.ptable.com/
wolfe8
  • wolfe8
I mean, write a balanced equation first.

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anonymous
  • anonymous
So..\[N _{2}(g) + h _{2}(g) \rightarrow NH _{3}\]
anonymous
  • anonymous
Is that the right equation?
anonymous
  • anonymous
\[N _{2}+3H _{2} \rightarrow 2NH _{3}\]
wolfe8
  • wolfe8
Oh my the equation editor is not working for me but I can see it. From here can you just use normal typing? Notice that the equation is not balanced. You have 2 N on the left and one on the right. And you have 2 H on the left and 3 on the right.
anonymous
  • anonymous
so N2 + 3H2 = 2NH3
wolfe8
  • wolfe8
Right. So now, you know how much H2 you used. Can you fine the number of moles of it? http://erhs.rcsnc.org/UserFiles/Servers/Server_4766394/Image/Donna%20Scofield/mole%20conversion%20map.bmp
anonymous
  • anonymous
Uh...Walk me through?
wolfe8
  • wolfe8
Sure. Do you know how to find the number of moles?
anonymous
  • anonymous
I know a mole is 6.02 * 10^23 thats about it
wolfe8
  • wolfe8
That is the Avogadro number - the number of objects in 1 mole of substance. But I'm sorry I misread the question. You are already given the number of moles. So here, from our balanced equation N2 + 3H2 = 2NH3 we can see that 3 parts of H2 produces 2 parts of NH3. What do you think we will do to get the moles of NH3?
anonymous
  • anonymous
Theres some formuala...
wolfe8
  • wolfe8
Nah. You have 24 mol which equals to 3 parts. Find for one part and multiple by 2 to get the mols of NH3
anonymous
  • anonymous
Uhm...One part meaning?
wolfe8
  • wolfe8
One proportion by ratio
anonymous
  • anonymous
Can you show me, I feel so lost...
wolfe8
  • wolfe8
Sure. So 24 mol is equal to 3 parts of H2 we use based on the equation so we divide 24 by 3. Then we know we get 2 parts of NH3 from the equation so we multiply it by 2
wolfe8
  • wolfe8
24/3*2 Get it? Want me to show it where there's whiteboard and mic?
anonymous
  • anonymous
Yeah!
anonymous
  • anonymous
so would it be 4 as the final answer?
wolfe8
  • wolfe8
Yeah. 4 mols. Do you understand what we did though?
wolfe8
  • wolfe8
NOOOOOO. 24/3 is 8 multiplied by 2 is 16
anonymous
  • anonymous
You know there is 24 mol. In 3 equal parts oh H2 and 2 equal parts of NH3?
anonymous
  • anonymous
Where do you get that information though? and oh okay just error in what comes first! sorry
wolfe8
  • wolfe8
Right. This is why we always need the balanced equation for stoichiometry.
anonymous
  • anonymous
Can you show me on the whiteboard?
wolfe8
  • wolfe8
Sure. Can you make a meeting on twiddla.com ? I can't because I already made one. Sent the link to me in PM
anonymous
  • anonymous
Actually its okay! i think i understood! Thanks so much for the help
wolfe8
  • wolfe8
Alright good job. Have a good night

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