Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Ammonia, NH3, is produced through a combination reaction involving N2(g) and H2(g). If 24.0 mol of H2(g) react with excess N2(g), how many moles of ammonia are produced?

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

I need to know how to solve this, I'm a bit rusty on my moles.
First, make sure the equation is balanced. Next, can you find the number of moles of whatever substance you have? Use this:
I mean, write a balanced equation first.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

So..\[N _{2}(g) + h _{2}(g) \rightarrow NH _{3}\]
Is that the right equation?
\[N _{2}+3H _{2} \rightarrow 2NH _{3}\]
Oh my the equation editor is not working for me but I can see it. From here can you just use normal typing? Notice that the equation is not balanced. You have 2 N on the left and one on the right. And you have 2 H on the left and 3 on the right.
so N2 + 3H2 = 2NH3
Right. So now, you know how much H2 you used. Can you fine the number of moles of it?
Uh...Walk me through?
Sure. Do you know how to find the number of moles?
I know a mole is 6.02 * 10^23 thats about it
That is the Avogadro number - the number of objects in 1 mole of substance. But I'm sorry I misread the question. You are already given the number of moles. So here, from our balanced equation N2 + 3H2 = 2NH3 we can see that 3 parts of H2 produces 2 parts of NH3. What do you think we will do to get the moles of NH3?
Theres some formuala...
Nah. You have 24 mol which equals to 3 parts. Find for one part and multiple by 2 to get the mols of NH3
Uhm...One part meaning?
One proportion by ratio
Can you show me, I feel so lost...
Sure. So 24 mol is equal to 3 parts of H2 we use based on the equation so we divide 24 by 3. Then we know we get 2 parts of NH3 from the equation so we multiply it by 2
24/3*2 Get it? Want me to show it where there's whiteboard and mic?
so would it be 4 as the final answer?
Yeah. 4 mols. Do you understand what we did though?
NOOOOOO. 24/3 is 8 multiplied by 2 is 16
You know there is 24 mol. In 3 equal parts oh H2 and 2 equal parts of NH3?
Where do you get that information though? and oh okay just error in what comes first! sorry
Right. This is why we always need the balanced equation for stoichiometry.
Can you show me on the whiteboard?
Sure. Can you make a meeting on ? I can't because I already made one. Sent the link to me in PM
Actually its okay! i think i understood! Thanks so much for the help
Alright good job. Have a good night

Not the answer you are looking for?

Search for more explanations.

Ask your own question