kaylala
  • kaylala
Trigonometric Equation 2tan^2A + 3secA = 0
Mathematics
chestercat
  • chestercat
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kaylala
  • kaylala
@hartnn Another one please
hartnn
  • hartnn
which pythagorean identities do you know ?
kaylala
  • kaylala
I've bee through all except for the half identities

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kaylala
  • kaylala
hartnn
  • hartnn
so which identity relates tan^2 A and sec^2 A ?
kaylala
  • kaylala
Sin?
kaylala
  • kaylala
I mean cos?
hartnn
  • hartnn
ever sen this ? \(\\tan^2 A =sec^2A-1\) ? use it here
kaylala
  • kaylala
Yes. I'm familiar with that Wait. Let me try
kaylala
  • kaylala
I got 2x^2+3x-2 Is it right? So i may move on
hartnn
  • hartnn
yes, that = 0 remember its an equation, not an expression
kaylala
  • kaylala
Oh right
kaylala
  • kaylala
How'll this be nothing will equal to 3x?
kaylala
  • kaylala
hartnn
  • hartnn
what ? i didn't get your question...
hartnn
  • hartnn
2x^2+3x-2 = 0 x= ..... x=....
kaylala
  • kaylala
Oh sorry What i meant was what should i do next? How do i find x? I cant use the FOIL method.
hartnn
  • hartnn
factor method. 2 numbers with sum = +3 and product = -4
kaylala
  • kaylala
Got it Wait
kaylala
  • kaylala
Sec = 1/2 Sec={no solution Sec=-2 No solution ????? I dont know Hpw's this? @hartnn
hartnn
  • hartnn
sec A can be -2
kaylala
  • kaylala
I dont see any negative 2 in the graph list Sec A =-2
hartnn
  • hartnn
sec A = -2 secA = 1/cos A cos A = -1/2 when ?
kaylala
  • kaylala
I dont see any cos A =-1/2 There is only cos A=1/2
kaylala
  • kaylala
Or did i get it wrong?
kaylala
  • kaylala
hartnn
  • hartnn
how about angles 120 and 210 ?
kaylala
  • kaylala
Where did you get that. Those arent in the graph that was given to us
hartnn
  • hartnn
http://en.wikipedia.org/wiki/File:Unit_circle_angles_color.svg
kaylala
  • kaylala
Oh i see now So will the answer for secA=-2 or cosA=-1/2 be: A={120,210}
kaylala
  • kaylala
Is that it already? How about sec=1/2? Does it really have no solution? @hartnn
hartnn
  • hartnn
yes. in the range 0 to 360. range of sec function does not include values between -1 and 1 so, sec A = 1/2 will have no solution, (in the same way cos A = 2 have no solution)
kaylala
  • kaylala
Okay thanks again
hartnn
  • hartnn
welcome ^_^

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