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kaylala

Trigonometric Equation 2tan^2A + 3secA = 0

  • 2 months ago
  • 2 months ago

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  1. kaylala
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    @hartnn Another one please

    • 2 months ago
  2. hartnn
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    which pythagorean identities do you know ?

    • 2 months ago
  3. kaylala
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    I've bee through all except for the half identities

    • 2 months ago
  4. kaylala
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    @hartnn

    • 2 months ago
  5. hartnn
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    so which identity relates tan^2 A and sec^2 A ?

    • 2 months ago
  6. kaylala
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    Sin?

    • 2 months ago
  7. kaylala
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    I mean cos?

    • 2 months ago
  8. hartnn
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    ever sen this ? \(\\tan^2 A =sec^2A-1\) ? use it here

    • 2 months ago
  9. kaylala
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    Yes. I'm familiar with that Wait. Let me try

    • 2 months ago
  10. kaylala
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    I got 2x^2+3x-2 Is it right? So i may move on

    • 2 months ago
  11. hartnn
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    yes, that = 0 remember its an equation, not an expression

    • 2 months ago
  12. kaylala
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    Oh right

    • 2 months ago
  13. kaylala
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    How'll this be nothing will equal to 3x?

    • 2 months ago
  14. kaylala
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    @hartnn ^

    • 2 months ago
  15. hartnn
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    what ? i didn't get your question...

    • 2 months ago
  16. hartnn
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    2x^2+3x-2 = 0 x= ..... x=....

    • 2 months ago
  17. kaylala
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    Oh sorry What i meant was what should i do next? How do i find x? I cant use the FOIL method.

    • 2 months ago
  18. hartnn
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    factor method. 2 numbers with sum = +3 and product = -4

    • 2 months ago
  19. kaylala
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    Got it Wait

    • 2 months ago
  20. kaylala
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    Sec = 1/2 Sec={no solution Sec=-2 No solution ????? I dont know Hpw's this? @hartnn

    • 2 months ago
  21. hartnn
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    sec A can be -2

    • 2 months ago
  22. kaylala
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    I dont see any negative 2 in the graph list Sec A =-2

    • 2 months ago
  23. hartnn
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    sec A = -2 secA = 1/cos A cos A = -1/2 when ?

    • 2 months ago
  24. kaylala
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    I dont see any cos A =-1/2 There is only cos A=1/2

    • 2 months ago
  25. kaylala
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    Or did i get it wrong?

    • 2 months ago
  26. kaylala
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    @hartnn ^

    • 2 months ago
  27. hartnn
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    how about angles 120 and 210 ?

    • 2 months ago
  28. kaylala
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    Where did you get that. Those arent in the graph that was given to us

    • 2 months ago
  29. hartnn
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    http://en.wikipedia.org/wiki/File:Unit_circle_angles_color.svg

    • 2 months ago
  30. kaylala
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    Oh i see now So will the answer for secA=-2 or cosA=-1/2 be: A={120,210}

    • 2 months ago
  31. kaylala
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    Is that it already? How about sec=1/2? Does it really have no solution? @hartnn

    • 2 months ago
  32. hartnn
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    yes. in the range 0 to 360. range of sec function does not include values between -1 and 1 so, sec A = 1/2 will have no solution, (in the same way cos A = 2 have no solution)

    • 2 months ago
  33. kaylala
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    Okay thanks again

    • 2 months ago
  34. hartnn
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    welcome ^_^

    • 2 months ago
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