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kaylala

  • one year ago

Trigonometric Equation 2tan^2A + 3secA = 0

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  1. kaylala
    • one year ago
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    @hartnn Another one please

  2. hartnn
    • one year ago
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    which pythagorean identities do you know ?

  3. kaylala
    • one year ago
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    I've bee through all except for the half identities

  4. kaylala
    • one year ago
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    @hartnn

  5. hartnn
    • one year ago
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    so which identity relates tan^2 A and sec^2 A ?

  6. kaylala
    • one year ago
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    Sin?

  7. kaylala
    • one year ago
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    I mean cos?

  8. hartnn
    • one year ago
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    ever sen this ? \(\\tan^2 A =sec^2A-1\) ? use it here

  9. kaylala
    • one year ago
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    Yes. I'm familiar with that Wait. Let me try

  10. kaylala
    • one year ago
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    I got 2x^2+3x-2 Is it right? So i may move on

  11. hartnn
    • one year ago
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    yes, that = 0 remember its an equation, not an expression

  12. kaylala
    • one year ago
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    Oh right

  13. kaylala
    • one year ago
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    How'll this be nothing will equal to 3x?

  14. kaylala
    • one year ago
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    @hartnn ^

  15. hartnn
    • one year ago
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    what ? i didn't get your question...

  16. hartnn
    • one year ago
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    2x^2+3x-2 = 0 x= ..... x=....

  17. kaylala
    • one year ago
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    Oh sorry What i meant was what should i do next? How do i find x? I cant use the FOIL method.

  18. hartnn
    • one year ago
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    factor method. 2 numbers with sum = +3 and product = -4

  19. kaylala
    • one year ago
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    Got it Wait

  20. kaylala
    • one year ago
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    Sec = 1/2 Sec={no solution Sec=-2 No solution ????? I dont know Hpw's this? @hartnn

  21. hartnn
    • one year ago
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    sec A can be -2

  22. kaylala
    • one year ago
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    I dont see any negative 2 in the graph list Sec A =-2

  23. hartnn
    • one year ago
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    sec A = -2 secA = 1/cos A cos A = -1/2 when ?

  24. kaylala
    • one year ago
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    I dont see any cos A =-1/2 There is only cos A=1/2

  25. kaylala
    • one year ago
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    Or did i get it wrong?

  26. kaylala
    • one year ago
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    @hartnn ^

  27. hartnn
    • one year ago
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    how about angles 120 and 210 ?

  28. kaylala
    • one year ago
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    Where did you get that. Those arent in the graph that was given to us

  29. hartnn
    • one year ago
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    http://en.wikipedia.org/wiki/File:Unit_circle_angles_color.svg

  30. kaylala
    • one year ago
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    Oh i see now So will the answer for secA=-2 or cosA=-1/2 be: A={120,210}

  31. kaylala
    • one year ago
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    Is that it already? How about sec=1/2? Does it really have no solution? @hartnn

  32. hartnn
    • one year ago
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    yes. in the range 0 to 360. range of sec function does not include values between -1 and 1 so, sec A = 1/2 will have no solution, (in the same way cos A = 2 have no solution)

  33. kaylala
    • one year ago
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    Okay thanks again

  34. hartnn
    • one year ago
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    welcome ^_^

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