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kaylala Group TitleBest ResponseYou've already chosen the best response.1
@hartnn Another one please
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.3
which pythagorean identities do you know ?
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
I've bee through all except for the half identities
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.3
so which identity relates tan^2 A and sec^2 A ?
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
I mean cos?
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.3
ever sen this ? \(\\tan^2 A =sec^2A1\) ? use it here
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
Yes. I'm familiar with that Wait. Let me try
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
I got 2x^2+3x2 Is it right? So i may move on
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.3
yes, that = 0 remember its an equation, not an expression
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
How'll this be nothing will equal to 3x?
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
@hartnn ^
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.3
what ? i didn't get your question...
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.3
2x^2+3x2 = 0 x= ..... x=....
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
Oh sorry What i meant was what should i do next? How do i find x? I cant use the FOIL method.
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.3
factor method. 2 numbers with sum = +3 and product = 4
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
Got it Wait
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
Sec = 1/2 Sec={no solution Sec=2 No solution ????? I dont know Hpw's this? @hartnn
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.3
sec A can be 2
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
I dont see any negative 2 in the graph list Sec A =2
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.3
sec A = 2 secA = 1/cos A cos A = 1/2 when ?
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
I dont see any cos A =1/2 There is only cos A=1/2
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
Or did i get it wrong?
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
@hartnn ^
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.3
how about angles 120 and 210 ?
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
Where did you get that. Those arent in the graph that was given to us
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.3
http://en.wikipedia.org/wiki/File:Unit_circle_angles_color.svg
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
Oh i see now So will the answer for secA=2 or cosA=1/2 be: A={120,210}
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
Is that it already? How about sec=1/2? Does it really have no solution? @hartnn
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.3
yes. in the range 0 to 360. range of sec function does not include values between 1 and 1 so, sec A = 1/2 will have no solution, (in the same way cos A = 2 have no solution)
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
Okay thanks again
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.3
welcome ^_^
 10 months ago
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