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kaylala
 2 years ago
Find the value of the following using the concepts of both addition and subtraction formulas and reference angle:
tan (255)
kaylala
 2 years ago
Find the value of the following using the concepts of both addition and subtraction formulas and reference angle: tan (255)

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***[ISURU]***
 2 years ago
Best ResponseYou've already chosen the best response.1tan ( 225 ) =  tan ( 225) = tan ( phi + 75 ) =  tan 75 = tan ( 45 + 30)

***[ISURU]***
 2 years ago
Best ResponseYou've already chosen the best response.1\[ \tan ( 30 + 45) = \frac{ \sin(30 + 45) }{ \cos (30 + 45) }\]\[ \tan (30 + 45) =  \frac{ \sin30 \ \cos45 + \cos30 \ \sin45 }{ \cos 30 \ \cos 45  \sin30 \ \sin 45 }\]

***[ISURU]***
 2 years ago
Best ResponseYou've already chosen the best response.1\[ \tan ( 45 + 30) = \frac{ (\frac{ 1 }{ 2} \times \frac{ 1 }{ \sqrt{2} }) + (\frac{ \sqrt{3} }{ 2 }\times \frac{ 1 }{ \sqrt{2} })}{(\frac{ \sqrt{3} }{ 2 }\times \frac{ 1 }{ \sqrt{2} })(\frac{ 1 }{ 2 }\times \frac{ 1 }{ \sqrt{2} } ) }\]

***[ISURU]***
 2 years ago
Best ResponseYou've already chosen the best response.1\[ \tan 75 = \frac{ 1 + \sqrt{3} }{ \sqrt{3}  1} = \frac{ ( 1 + \sqrt{3})(\sqrt{3} +1) }{ (\sqrt{3} 1)(\sqrt{3} +1) } = \frac{ 1 +3 + 2\sqrt{3} }{ 2} =  2 + \sqrt{3} = \tan(225)\]

***[ISURU]***
 2 years ago
Best ResponseYou've already chosen the best response.1\[\tan (225) = ( 2 + \sqrt{3} )\]

kaylala
 2 years ago
Best ResponseYou've already chosen the best response.0yes got it. thanks @***[ISURU]***
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