anonymous
  • anonymous
.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
I think the answer is supposed to be zero but how I get there?
anonymous
  • anonymous
I took the deribative of the top and the bottom but I just ended up at (100n^99)/(e^n) and don't know where to go from here.
myininaya
  • myininaya
You should see a pattern in the derivatives.

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myininaya
  • myininaya
you can do l'hospitals again
myininaya
  • myininaya
well nevermind kainui did it for you
myininaya
  • myininaya
You could have left it. Maybe it is hard for some people to reach that.
Kainui
  • Kainui
The point is, L'H rule says the limit of a ratio is the same as the limit of the ratio of their derivatives as well. So we can just see that eventually n^100 will eventually become a constant while the bottom will always be a function of n.
myininaya
  • myininaya
If it is hard for you to see the constant kainui got. You can look at a an example with a lesser power
myininaya
  • myininaya
Like what would f^(4)(x) look like if we had f(x)=x^5
anonymous
  • anonymous
I kinda understand what kainui said
myininaya
  • myininaya
coolness
Kainui
  • Kainui
Sorry, I realized I wasn't being cryptic enough, so I went more cryptical. =P
anonymous
  • anonymous
So does the limit even exist?
Kainui
  • Kainui
\[\frac{ d^n }{ dx^n }(x^n)=n!\] just for fun -- Yeah, it even exists and it's even zero. @jennisicle
anonymous
  • anonymous
Ah, that's what I thought, thanks!

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