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jennisicle Group TitleBest ResponseYou've already chosen the best response.1
I think the answer is supposed to be zero but how I get there?
 8 months ago

jennisicle Group TitleBest ResponseYou've already chosen the best response.1
I took the deribative of the top and the bottom but I just ended up at (100n^99)/(e^n) and don't know where to go from here.
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
You should see a pattern in the derivatives.
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
you can do l'hospitals again
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
well nevermind kainui did it for you
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
You could have left it. Maybe it is hard for some people to reach that.
 8 months ago

Kainui Group TitleBest ResponseYou've already chosen the best response.1
The point is, L'H rule says the limit of a ratio is the same as the limit of the ratio of their derivatives as well. So we can just see that eventually n^100 will eventually become a constant while the bottom will always be a function of n.
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
If it is hard for you to see the constant kainui got. You can look at a an example with a lesser power
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Like what would f^(4)(x) look like if we had f(x)=x^5
 8 months ago

jennisicle Group TitleBest ResponseYou've already chosen the best response.1
I kinda understand what kainui said
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
coolness
 8 months ago

Kainui Group TitleBest ResponseYou've already chosen the best response.1
Sorry, I realized I wasn't being cryptic enough, so I went more cryptical. =P
 8 months ago

jennisicle Group TitleBest ResponseYou've already chosen the best response.1
So does the limit even exist?
 8 months ago

Kainui Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{ d^n }{ dx^n }(x^n)=n!\] just for fun  Yeah, it even exists and it's even zero. @jennisicle
 8 months ago

jennisicle Group TitleBest ResponseYou've already chosen the best response.1
Ah, that's what I thought, thanks!
 8 months ago
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