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lesliemolina
Which of the following best defines 4 to the power of 2 over 3? Square root of 16 Cube root of 4 Square root of 4 Cube root of 16
\[4^{\frac{2}{3}}=\sqrt[3]{4^2}\]
since \(4^2=16\) it is also \(\sqrt[3]{16}\)
\[4^{2/3}=(4^{1/3})^{2}=(\sqrt{2})^{2}=2\]
Therefore, 2 is the square root of 4.
nooooo because \[\sqrt[3]{4}^2 \] so it would be 3sqr16
@satellite73 Which answer is correct?
yeah what is the answer choice???