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\[4^{\frac{2}{3}}=\sqrt[3]{4^2}\]

since \(4^2=16\) it is also \(\sqrt[3]{16}\)

\[4^{2/3}=(4^{1/3})^{2}=(\sqrt{2})^{2}=2\]

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Therefore, 2 is the square root of 4.

nooooo because \[\sqrt[3]{4}^2 \] so it would be 3sqr16

@satellite73
Which answer is correct?

yeah what is the answer choice???

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