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StClowers
 one year ago
Twelve different video games showing substance use were observed and the duration times of game play (in seconds) are listed below. The design of the study justifies the assumption that the sample can be treated as a simple random sample. Use the data to construct a 90% confidence interval estimate of µ, the mean duration of game play.
4049
3881
3854
4030
4324
4816
4661
4040
5001
4821
4327
4326
What is the confidence interval estimate of the population mean µ ? __ < µ < __ (round to one decimal place as needed)
StClowers
 one year ago
Twelve different video games showing substance use were observed and the duration times of game play (in seconds) are listed below. The design of the study justifies the assumption that the sample can be treated as a simple random sample. Use the data to construct a 90% confidence interval estimate of µ, the mean duration of game play. 4049 3881 3854 4030 4324 4816 4661 4040 5001 4821 4327 4326 What is the confidence interval estimate of the population mean µ ? __ < µ < __ (round to one decimal place as needed)

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douglaswinslowcooper
 one year ago
Best ResponseYou've already chosen the best response.0Get the mean, mu = sum of values divided by number of values, n Get the variance = sum (valuemean)^2/(n1) get the standard deviation s.d. = sqrt(variance) Get the standard error of the mean from s.e. = s.d./sqrt(n) Assume a normal (Gaussian) distribution approximately for means. Check table of Gaussian distribuiotn to find how many + s.e. you need to include 90% of the values. For example + 2 s.e includes 95% of values. Interpretation: means are more nearly Gaussian than underlying distributions from which they come, and 90% of the true means would be expected to lie within + k s.d. of the sample mean, if only random error.

StClowers
 one year ago
Best ResponseYou've already chosen the best response.0huh? I have no clue what you mean. lol

StClowers
 one year ago
Best ResponseYou've already chosen the best response.0I need help pluggin in the numbers
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