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  1. sleung
    • 2 years ago
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    Medals 1

    \[\frac{ d ^{2} +d-30}{ d ^{2}+3d-40 }+\frac{ d ^{2}+14d+48 }{ d ^{2}-2d-48 }\]\[\frac{ (d+6)(d-5) }{ (d+8)(d-5) }+\frac{ (d+6)(d+8) }{ (d-8)(d+6) }\]\[\frac{ (d+6)(d-8) }{ (d+8)(d-8) }+\frac{ (d+8)^{2} }{ (d+8)(d-8) }\]\[\frac{ (d ^{2}-2d-48)+(d ^{2}+16d+64) }{ (d+8)(d-8) }\]

  2. sleung
    • 2 years ago
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    Medals 1

    I think you can do the rest from here.

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