A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 2 years ago
For a linear function, f(1) = 8 and f(7) = 10. If f(k) = 5, what is the value of k?
anonymous
 2 years ago
For a linear function, f(1) = 8 and f(7) = 10. If f(k) = 5, what is the value of k?

This Question is Closed

campbell_st
 2 years ago
Best ResponseYou've already chosen the best response.1the basic form is y = mx + b start by finding the slope of the line \[m = \frac{f(7)  f(1)}{7  1}\] or \[m = \frac{10 8}{7  1}\] so whats the slope of the line...?

campbell_st
 2 years ago
Best ResponseYou've already chosen the best response.1oops... you need to find the equation before you can find k

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.3Or you could solve the following for k instead of finding the equation of a line: \[\frac{f(7)f(1)}{71}=\frac{f(k)f(1)}{k1}\]

jdoe0001
 2 years ago
Best ResponseYou've already chosen the best response.1\(\bf f(1) = 8 \implies (1,8) \qquad f(7) = 10\implies (7,10) \\ \quad \\ \quad \\ \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 1}}\quad ,&{\color{blue}{ 8}})\quad &({\color{red}{ 7}}\quad ,&{\color{blue}{ 10}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}{\color{blue}{ y_1}}}{{\color{red}{ x_2}}{\color{red}{ x_1}}} \\ \quad \\ y{\color{blue}{ y_1}}={\color{green}{ m}}(x{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\ \qquad \uparrow\\ \textit{pointslope form} \)

jdoe0001
 2 years ago
Best ResponseYou've already chosen the best response.1f(k) = 5 > (k, 5) or "what is the value of "x" if y=5"?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.