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## anonymous 2 years ago what is the tangent line of F(x)= sin^2 x at points (pi/4,1/2)

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1. myininaya

Find the derivative for your function to find the slope at pi/4

2. richyw

$F(x)=\sin^2x$$F '(x)=2\sin x\cos x$$F'(\pi/4)=2\sin\left(\frac{\pi}{4}\right)\cos\left(\frac{\pi}{4}\right)$$=2\left(\frac{\sqrt{2}}{2}\right)\left(\frac{\sqrt{2}}{2}\right)=1$

3. richyw

now you have the slope (I think haha) and then you also have a point $$(\pi/4,1/2)$$ so then you have $\pi/4+b=1/2$$b = 1/2-\pi/4$so $$g(x)=x+1/2-\pi/4$$ is the tangent line. At least I think. I have a bad hangover.

4. richyw

5. anonymous

Thank you

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