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anonymous

  • 2 years ago

Find a cubic function with the given zeros. Square root of six., - Square root of six., -3 f(x) = x3 - 3x2 - 6x - 18 f(x) = x3 + 3x2 - 6x - 18 f(x) = x3 + 3x2 + 6x - 18 f(x) = x3 + 3x2 - 6x + 18

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  1. triciaal
    • 2 years ago
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    (x +6)(x-6)(x+3) = 0

  2. anonymous
    • 2 years ago
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    i have x^3+3x^2-36-108=0

  3. triciaal
    • 2 years ago
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    you have to multiply each term someone else was also responding. i guess he changed his mind i will do it now

  4. triciaal
    • 2 years ago
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    you forgot your x then factor the 6

  5. triciaal
    • 2 years ago
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    x^3 + 3x^2-36x-108

  6. anonymous
    • 2 years ago
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    \[(x-\sqrt{6})(x+\sqrt{6})(x+3)=0\] I think you can expand from here.

  7. anonymous
    • 2 years ago
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    how did you get it?

  8. triciaal
    • 2 years ago
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    sorry i made a mistake it should be as above rt 6

  9. triciaal
    • 2 years ago
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    (x-rt6)(x +rt6)(x+3) recognise the difference of 2 squares? (x^2-6)(x+3) expaND X^3-6X+3X^2-18 Rearrange to put in order of degree x^3 +3x^2 -6x-18

  10. triciaal
    • 2 years ago
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    sorry recognize

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