anonymous
  • anonymous
Find a cubic function with the given zeros. Square root of six., - Square root of six., -3 f(x) = x3 - 3x2 - 6x - 18 f(x) = x3 + 3x2 - 6x - 18 f(x) = x3 + 3x2 + 6x - 18 f(x) = x3 + 3x2 - 6x + 18
Calculus1
katieb
  • katieb
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triciaal
  • triciaal
(x +6)(x-6)(x+3) = 0
anonymous
  • anonymous
i have x^3+3x^2-36-108=0
triciaal
  • triciaal
you have to multiply each term someone else was also responding. i guess he changed his mind i will do it now

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triciaal
  • triciaal
you forgot your x then factor the 6
triciaal
  • triciaal
x^3 + 3x^2-36x-108
anonymous
  • anonymous
\[(x-\sqrt{6})(x+\sqrt{6})(x+3)=0\] I think you can expand from here.
anonymous
  • anonymous
how did you get it?
triciaal
  • triciaal
sorry i made a mistake it should be as above rt 6
triciaal
  • triciaal
(x-rt6)(x +rt6)(x+3) recognise the difference of 2 squares? (x^2-6)(x+3) expaND X^3-6X+3X^2-18 Rearrange to put in order of degree x^3 +3x^2 -6x-18
triciaal
  • triciaal
sorry recognize

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