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stupidinmath

  • 2 years ago

what is the circumference of the circle x^2+y^2-10y-36=0? a. 38 b. 49 c. 54 d. 125 e. 192

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  1. eliassaab
    • 2 years ago
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    \[ x^2+y^2-10y-36=0\\ x^2+y^2-10y+25 -25-36=0\\ x^2 +(y-5)^2 = 61=r^2\\ r=\sqrt{61}\\ \]

  2. eliassaab
    • 2 years ago
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    \[ 2 \pi r = 2 \pi \sqrt{61}=49.0732 \]

  3. eliassaab
    • 2 years ago
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    It seems b is the answer

  4. jmiller22
    • 2 years ago
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    Yes it is B.49

  5. stupidinmath
    • 2 years ago
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    oh, thanks!

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