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andijo76
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In a sample of 7 cars each car was tested for nitrogenoxide emissions (in grams per mile) and the following results are obtained
0.18, 0.16, 0.08, 0.06,0.17,0.12,0.15 assuming that this sample is representative of the cars in use. cosntruct a 98% confidence interval estimate of the mean amount of nitrogen=oxide emissions for all cars. if the epa requires that nitrogen oxide emissions can be less than 0.165g.mi we can safely conclude that requirement is being met
A)what is the confidence interval estimate of the mean amount of nitrogenoxide emissions for all cars
___g/mi<u<___g/mi
 8 months ago
 8 months ago
andijo76 Group Title
In a sample of 7 cars each car was tested for nitrogenoxide emissions (in grams per mile) and the following results are obtained 0.18, 0.16, 0.08, 0.06,0.17,0.12,0.15 assuming that this sample is representative of the cars in use. cosntruct a 98% confidence interval estimate of the mean amount of nitrogen=oxide emissions for all cars. if the epa requires that nitrogen oxide emissions can be less than 0.165g.mi we can safely conclude that requirement is being met A)what is the confidence interval estimate of the mean amount of nitrogenoxide emissions for all cars ___g/mi<u<___g/mi
 8 months ago
 8 months ago

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StClowers Group TitleBest ResponseYou've already chosen the best response.0
I have this same question! lol
 8 months ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.2
The first step is to calculate the sample mean by adding the seven values and dividing by 7: \[\bar{x}=\frac{0.18+0.16+0.08+0.06+0.17+0.12+0.15}{7}=\frac{0.92}{7}=0.13143\]
 8 months ago

StClowers Group TitleBest ResponseYou've already chosen the best response.0
@kropot72, then how do you get the __g/mi <u< __g/mi ??
 8 months ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.2
The next step is to calculate the sample standard deviation, s.
 8 months ago

StClowers Group TitleBest ResponseYou've already chosen the best response.0
not sure how to do that..
 8 months ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.2
You can use a calculator with statistical functions to calculate the sample standard deviation, s.
 8 months ago

andijo76 Group TitleBest ResponseYou've already chosen the best response.0
x= i got a totally different answer than you did
 8 months ago

andijo76 Group TitleBest ResponseYou've already chosen the best response.0
and the sd i think is 0.046
 8 months ago

StClowers Group TitleBest ResponseYou've already chosen the best response.0
how did you get the sd @andijo76
 8 months ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.2
@andijo76 what did you get for the sum of the seven data values?
 8 months ago

andijo76 Group TitleBest ResponseYou've already chosen the best response.0
i found a website back when i was doing pre algebra that helps me figuring out some calculations
 8 months ago

andijo76 Group TitleBest ResponseYou've already chosen the best response.0
the sum i got was 0.842/7=0.1203
 8 months ago

StClowers Group TitleBest ResponseYou've already chosen the best response.0
does anyone know how to input this into the Ti84?
 8 months ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.2
@andijo76 The correct sum of the seven data values is 0.92.
 8 months ago

andijo76 Group TitleBest ResponseYou've already chosen the best response.0
im trying to figure out how i got that lol
 8 months ago

andijo76 Group TitleBest ResponseYou've already chosen the best response.0
is the sd right tho
 8 months ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.2
My calculator gives the value for the sample standard deviation of s = 0.4634
 8 months ago

StClowers Group TitleBest ResponseYou've already chosen the best response.0
@kropot72 how did you input the sd in the calc?
 8 months ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.2
My calculator is a Casio fx82 AU PLUS. I just followed the instructions in the User's Guide.
 8 months ago

andijo76 Group TitleBest ResponseYou've already chosen the best response.0
im sorry you are correct i dont know what i did but i fixed it i think i rounded one decimal or something
 8 months ago

andijo76 Group TitleBest ResponseYou've already chosen the best response.0
there is a website that gives you sd i will paste what it said
 8 months ago

andijo76 Group TitleBest ResponseYou've already chosen the best response.0
Simplify the result. σ=0.046344719225 The standard deviation should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise. 0.046
 8 months ago

StClowers Group TitleBest ResponseYou've already chosen the best response.0
@andijo76 can you paste the link to the website?
 8 months ago

andijo76 Group TitleBest ResponseYou've already chosen the best response.0
www.mathway.com it costs 20 a month though i keep it for my kids it helps you figure out things step by step
 8 months ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.2
The final calculation uses the following formula: \[\bar{x}2.576\frac{s}{\sqrt{n}}<\mu<\bar{x}+2.576\frac{s}{\sqrt{n}}\] Substituting values gives the confidence interval for the population mean as follows: \[0.131432.576\frac{0.046}{\sqrt{7}}<\mu<0.13143+2.576\frac{0.046}{\sqrt{7}}\]
 8 months ago

StClowers Group TitleBest ResponseYou've already chosen the best response.0
where did you get the 2.576?
 8 months ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.2
The value 2.576 is determined by an inverse normal technique. However it can be found in tables for use in calculating confidence intervals.
 8 months ago

andijo76 Group TitleBest ResponseYou've already chosen the best response.0
i know i am going to sound stupid but how do i figure _g/mi<u<_g/mi was that the answer
 8 months ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.2
When you have calculated the two values for the confidence interval, just put the lower value where the first underscore is and the higher value where the right hand underscore is.
 8 months ago

andijo76 Group TitleBest ResponseYou've already chosen the best response.0
i got for the first one 44.6558 so i am thinking it is i just have to put round and put it in 3 decimal places
 8 months ago

StClowers Group TitleBest ResponseYou've already chosen the best response.0
so is this the answer then: .0866 g/mi< .1762 g/mi ?! @kropot72
 8 months ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.2
Looks correct to me :)
 8 months ago

andijo76 Group TitleBest ResponseYou've already chosen the best response.0
yeah i forgot the point haha
 8 months ago

andijo76 Group TitleBest ResponseYou've already chosen the best response.0
it amazing how that works hey
 8 months ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.2
It is a very powerful technique!
 8 months ago

andijo76 Group TitleBest ResponseYou've already chosen the best response.0
thank you so much for your help
 8 months ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.2
You're welcome :)
 8 months ago

StClowers Group TitleBest ResponseYou've already chosen the best response.0
lol great! thanks!!
 8 months ago
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