andijo76
  • andijo76
In a sample of 7 cars each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results are obtained 0.18, 0.16, 0.08, 0.06,0.17,0.12,0.15 assuming that this sample is representative of the cars in use. cosntruct a 98% confidence interval estimate of the mean amount of nitrogen=oxide emissions for all cars. if the epa requires that nitrogen oxide emissions can be less than 0.165g.mi we can safely conclude that requirement is being met A)what is the confidence interval estimate of the mean amount of nitrogen-oxide emissions for all cars ___g/mi
Statistics
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
I have this same question! lol
kropot72
  • kropot72
The first step is to calculate the sample mean by adding the seven values and dividing by 7: \[\bar{x}=\frac{0.18+0.16+0.08+0.06+0.17+0.12+0.15}{7}=\frac{0.92}{7}=0.13143\]
anonymous
  • anonymous
@kropot72, then how do you get the __g/mi

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More answers

kropot72
  • kropot72
The next step is to calculate the sample standard deviation, s.
anonymous
  • anonymous
not sure how to do that..
kropot72
  • kropot72
You can use a calculator with statistical functions to calculate the sample standard deviation, s.
andijo76
  • andijo76
x= i got a totally different answer than you did
andijo76
  • andijo76
and the sd i think is 0.046
anonymous
  • anonymous
how did you get the sd @andijo76
kropot72
  • kropot72
@andijo76 what did you get for the sum of the seven data values?
andijo76
  • andijo76
i found a website back when i was doing pre algebra that helps me figuring out some calculations
andijo76
  • andijo76
the sum i got was 0.842/7=0.1203
anonymous
  • anonymous
does anyone know how to input this into the Ti84?
kropot72
  • kropot72
@andijo76 The correct sum of the seven data values is 0.92.
andijo76
  • andijo76
im trying to figure out how i got that lol
andijo76
  • andijo76
is the sd right tho
kropot72
  • kropot72
My calculator gives the value for the sample standard deviation of s = 0.4634
anonymous
  • anonymous
@kropot72 how did you input the sd in the calc?
kropot72
  • kropot72
My calculator is a Casio fx-82 AU PLUS. I just followed the instructions in the User's Guide.
andijo76
  • andijo76
im sorry you are correct i dont know what i did but i fixed it i think i rounded one decimal or something
andijo76
  • andijo76
there is a website that gives you sd i will paste what it said
andijo76
  • andijo76
Simplify the result. σ=0.046344719225 The standard deviation should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise. 0.046
anonymous
  • anonymous
@andijo76 can you paste the link to the website?
andijo76
  • andijo76
www.mathway.com it costs 20 a month though i keep it for my kids it helps you figure out things step by step
kropot72
  • kropot72
The final calculation uses the following formula: \[\bar{x}-2.576\frac{s}{\sqrt{n}}<\mu<\bar{x}+2.576\frac{s}{\sqrt{n}}\] Substituting values gives the confidence interval for the population mean as follows: \[0.13143-2.576\frac{0.046}{\sqrt{7}}<\mu<0.13143+2.576\frac{0.046}{\sqrt{7}}\]
anonymous
  • anonymous
where did you get the 2.576?
kropot72
  • kropot72
The value 2.576 is determined by an inverse normal technique. However it can be found in tables for use in calculating confidence intervals.
anonymous
  • anonymous
ok
andijo76
  • andijo76
i know i am going to sound stupid but how do i figure _g/mi
kropot72
  • kropot72
When you have calculated the two values for the confidence interval, just put the lower value where the first underscore is and the higher value where the right hand underscore is.
andijo76
  • andijo76
i got for the first one -44.6558 so i am thinking it is i just have to put round and put it in 3 decimal places
anonymous
  • anonymous
so is this the answer then: .0866 g/mi< .1762 g/mi ?! @kropot72
kropot72
  • kropot72
Looks correct to me :)
andijo76
  • andijo76
yeah i forgot the point haha
andijo76
  • andijo76
it amazing how that works hey
kropot72
  • kropot72
It is a very powerful technique!
andijo76
  • andijo76
thank you so much for your help
kropot72
  • kropot72
You're welcome :)
anonymous
  • anonymous
lol great! thanks!!

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