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sophiagarces32
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How would I solve for x in the equation: 0.406779661=.188ln(x)+2.6979?
 8 months ago
 8 months ago
sophiagarces32 Group Title
How would I solve for x in the equation: 0.406779661=.188ln(x)+2.6979?
 8 months ago
 8 months ago

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AndrewLentz Group TitleBest ResponseYou've already chosen the best response.0
isolate ln(x), so it should look like: ln(x) = (.4062.6979)/.188 and then to cancel out the natural log, have both sides be the exponent of e e^ln(x) = e^[(.4062.6979)/.188] so x = e^[(.4062.6979)/.188].
 7 months ago
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