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anonymous

  • 2 years ago

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  1. myininaya
    • 2 years ago
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    Try clearing the fractions by multiplying both sides by (b+1)(b-1)

  2. anonymous
    • 2 years ago
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    so 1 * (b+1) and 1 * (b-1)? @myininaya

  3. myininaya
    • 2 years ago
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    So (b-1)+(b+1)=2

  4. myininaya
    • 2 years ago
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    the b+1 will cancel in the first fraction the b-1 will cancel in the second fraction in the last fraction the b^2-1 will cancel because (b-1)(b+1) is the same as b^2-1

  5. myininaya
    • 2 years ago
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    Recall b^2-1=(b-1)(b+1)

  6. anonymous
    • 2 years ago
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    Ahh okay. So there are no solutions?

  7. anonymous
    • 2 years ago
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    @myininaya

  8. myininaya
    • 2 years ago
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    there is no solution very good. you knew that because 1 isn't in the domain of the original equation right?

  9. myininaya
    • 2 years ago
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    It should be (b-1)+(b+1)=2

  10. anonymous
    • 2 years ago
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    Ahh okay thanks. Changed it. Anything else?

  11. myininaya
    • 2 years ago
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    I think it looks fine.

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