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darkigloo
 11 months ago
Best ResponseYou've already chosen the best response.0the intersection points on the graph are (2,1) and (2,9)

darkigloo
 11 months ago
Best ResponseYou've already chosen the best response.0i did: \[\int\limits_{2}^{9} (x^2+2x+1(2x+5))dx \] and I got 605/3. But now I'm starting to think I should have switched the functions. like:\[\int\limits_{2}^{9} (2x+5)(x^2+2x+1))dx\]

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.0how did you get those pretty integer intersections? how did that one function magically appear?

darkigloo
 11 months ago
Best ResponseYou've already chosen the best response.0there's a picture of the two graphs and the intersections

darkigloo
 11 months ago
Best ResponseYou've already chosen the best response.0oh wait...i made a mistake. hold on.

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.0I'm suppose to ignore that one function?

darkigloo
 11 months ago
Best ResponseYou've already chosen the best response.0\[f(x)=x^2+2x+1 \] \[g(x)= 2x+5\]
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