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darkigloo
 9 months ago
Best ResponseYou've already chosen the best response.0the intersection points on the graph are (2,1) and (2,9)

darkigloo
 9 months ago
Best ResponseYou've already chosen the best response.0i did: \[\int\limits_{2}^{9} (x^2+2x+1(2x+5))dx \] and I got 605/3. But now I'm starting to think I should have switched the functions. like:\[\int\limits_{2}^{9} (2x+5)(x^2+2x+1))dx\]

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.0how did you get those pretty integer intersections? how did that one function magically appear?

darkigloo
 9 months ago
Best ResponseYou've already chosen the best response.0there's a picture of the two graphs and the intersections

darkigloo
 9 months ago
Best ResponseYou've already chosen the best response.0oh wait...i made a mistake. hold on.

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.0I'm suppose to ignore that one function?

darkigloo
 9 months ago
Best ResponseYou've already chosen the best response.0\[f(x)=x^2+2x+1 \] \[g(x)= 2x+5\]
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