Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Triangle Congruence and Similarity Help!

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

1 Attachment
Which equation can she use as statement 5? x:15 = 28:40 28:12 = x:(x + 15 ) x + 15 = 28 + 12 28:40 = x:(x + 15)
what do you think? Corresponding sides of similar triangles are proportional which means PS:PQ = PT:PR

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

I am not good with proofs
like... AT ALL
is it C ?
@atlas OH WAIT ITS A right? because PS:PQ = PT:PR
PR = x+15
Yes and PQ = 28 + 12
1 Attachment
that ratio is : \(28 : (28+12)\)
you need to take the other side ratio in similar way
1 Attachment
x: (x + 15) ?
Yes !!!!
both ratios are equal cuz triangles are similar
\(28 : (28+12) = x : (x+15)\)
yo whats 28+12 ?
so its D
D is \(\large \color{red}{\checkmark}\)
28:40 = x:(x + 15)
Thanks so much!
np :) thank atlas !
@atlas thanks lol

Not the answer you are looking for?

Search for more explanations.

Ask your own question