Based on recent records, the manager of a car painting center has determined the following probability distribution for the number of customers per day.
x 0 1 2 3 4 5
f(x) 0.06 0.16 0.26 0.23 0.1 0.19
If the center has the capacity to serve two customers per day. By how much must the capacity be increased so the probability of turning a customer away is no more than 0.10 ?

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Chebyshev's rule: \[1-\frac{ 1 }{ k ^{2} }\]I've learned this, yes

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