Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
wildmango
Group Title
If a baseball player has a batting average of 0.420, what is the probability that the player will get at least 2 hits in the next four times at bat?
 5 months ago
 5 months ago
wildmango Group Title
If a baseball player has a batting average of 0.420, what is the probability that the player will get at least 2 hits in the next four times at bat?
 5 months ago
 5 months ago

This Question is Open

wio Group TitleBest ResponseYou've already chosen the best response.1
Binomial distribution. Do you know it?
 5 months ago

wildmango Group TitleBest ResponseYou've already chosen the best response.0
No, can you help me solve this?
 5 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
You've never even heard of binomial distribution?
 5 months ago

wildmango Group TitleBest ResponseYou've already chosen the best response.0
Yes I've heard of it but It's not clear to me.
 5 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
Well. To get \(k\) success with \(n\) tries and each try has probability \(p\), we say the probability is: \[ {n\choose k}p^k(1p)^{nk} \]
 5 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
Will will bat 4 times. His probability of hitting it is 0.420. We want the probability he its it at least 2 times, meaning he hits it 2, 3, or 4 times.
 5 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
Can you try to figure out which number goes where?
 5 months ago

wildmango Group TitleBest ResponseYou've already chosen the best response.0
not really, I really don't get it..
 5 months ago

wildmango Group TitleBest ResponseYou've already chosen the best response.0
0.42(10.42)^4^2 This doesn't even look correct. Is there a format that I should know?
 5 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
In this case, there are 4 tries, so \(n=4\).
 5 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
So we have, so far \[ {4\choose k}p^k(1p)^{4k} \]
 5 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
The probability of success is given by batting average, so \(p=0.420\) and \(1p=0.580\). Now we have: \[ {4\choose k}(0.420)^k(0.580)^{4k} \]
 5 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
At least two hits... that mean 2 hits, 3 hits, or 4 hits.
 5 months ago

wildmango Group TitleBest ResponseYou've already chosen the best response.0
So then k is the # of hits then correct?
 5 months ago

wildmango Group TitleBest ResponseYou've already chosen the best response.0
Then I would replace the k with 2 to get the correct format?
 5 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
no, you need to find probabilities for 2, 3, and 4. Then combine them.
 5 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.