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wildmango
 one year ago
If a baseball player has a batting average of 0.420, what is the probability that the player will get at least 2 hits in the next four times at bat?
wildmango
 one year ago
If a baseball player has a batting average of 0.420, what is the probability that the player will get at least 2 hits in the next four times at bat?

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wio
 one year ago
Best ResponseYou've already chosen the best response.1Binomial distribution. Do you know it?

wildmango
 one year ago
Best ResponseYou've already chosen the best response.0No, can you help me solve this?

wio
 one year ago
Best ResponseYou've already chosen the best response.1You've never even heard of binomial distribution?

wildmango
 one year ago
Best ResponseYou've already chosen the best response.0Yes I've heard of it but It's not clear to me.

wio
 one year ago
Best ResponseYou've already chosen the best response.1Well. To get \(k\) success with \(n\) tries and each try has probability \(p\), we say the probability is: \[ {n\choose k}p^k(1p)^{nk} \]

wio
 one year ago
Best ResponseYou've already chosen the best response.1Will will bat 4 times. His probability of hitting it is 0.420. We want the probability he its it at least 2 times, meaning he hits it 2, 3, or 4 times.

wio
 one year ago
Best ResponseYou've already chosen the best response.1Can you try to figure out which number goes where?

wildmango
 one year ago
Best ResponseYou've already chosen the best response.0not really, I really don't get it..

wildmango
 one year ago
Best ResponseYou've already chosen the best response.00.42(10.42)^4^2 This doesn't even look correct. Is there a format that I should know?

wio
 one year ago
Best ResponseYou've already chosen the best response.1In this case, there are 4 tries, so \(n=4\).

wio
 one year ago
Best ResponseYou've already chosen the best response.1So we have, so far \[ {4\choose k}p^k(1p)^{4k} \]

wio
 one year ago
Best ResponseYou've already chosen the best response.1The probability of success is given by batting average, so \(p=0.420\) and \(1p=0.580\). Now we have: \[ {4\choose k}(0.420)^k(0.580)^{4k} \]

wio
 one year ago
Best ResponseYou've already chosen the best response.1At least two hits... that mean 2 hits, 3 hits, or 4 hits.

wildmango
 one year ago
Best ResponseYou've already chosen the best response.0So then k is the # of hits then correct?

wildmango
 one year ago
Best ResponseYou've already chosen the best response.0Then I would replace the k with 2 to get the correct format?

wio
 one year ago
Best ResponseYou've already chosen the best response.1no, you need to find probabilities for 2, 3, and 4. Then combine them.
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