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wildmango
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If a baseball player has a batting average of 0.420, what is the probability that the player will get at least 2 hits in the next four times at bat?
 6 months ago
 6 months ago
wildmango Group Title
If a baseball player has a batting average of 0.420, what is the probability that the player will get at least 2 hits in the next four times at bat?
 6 months ago
 6 months ago

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wio Group TitleBest ResponseYou've already chosen the best response.1
Binomial distribution. Do you know it?
 6 months ago

wildmango Group TitleBest ResponseYou've already chosen the best response.0
No, can you help me solve this?
 6 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
You've never even heard of binomial distribution?
 6 months ago

wildmango Group TitleBest ResponseYou've already chosen the best response.0
Yes I've heard of it but It's not clear to me.
 6 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
Well. To get \(k\) success with \(n\) tries and each try has probability \(p\), we say the probability is: \[ {n\choose k}p^k(1p)^{nk} \]
 6 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
Will will bat 4 times. His probability of hitting it is 0.420. We want the probability he its it at least 2 times, meaning he hits it 2, 3, or 4 times.
 6 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
Can you try to figure out which number goes where?
 6 months ago

wildmango Group TitleBest ResponseYou've already chosen the best response.0
not really, I really don't get it..
 6 months ago

wildmango Group TitleBest ResponseYou've already chosen the best response.0
0.42(10.42)^4^2 This doesn't even look correct. Is there a format that I should know?
 6 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
In this case, there are 4 tries, so \(n=4\).
 6 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
So we have, so far \[ {4\choose k}p^k(1p)^{4k} \]
 6 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
The probability of success is given by batting average, so \(p=0.420\) and \(1p=0.580\). Now we have: \[ {4\choose k}(0.420)^k(0.580)^{4k} \]
 6 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
At least two hits... that mean 2 hits, 3 hits, or 4 hits.
 6 months ago

wildmango Group TitleBest ResponseYou've already chosen the best response.0
So then k is the # of hits then correct?
 6 months ago

wildmango Group TitleBest ResponseYou've already chosen the best response.0
Then I would replace the k with 2 to get the correct format?
 6 months ago

wio Group TitleBest ResponseYou've already chosen the best response.1
no, you need to find probabilities for 2, 3, and 4. Then combine them.
 6 months ago
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