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sarah1017 Group Title

What is the standard form of the equation of an ellipse with foci at (+-3,0) and co-vertices at (0,+-5)? Please show all steps!

  • 5 months ago
  • 5 months ago

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  1. ganeshie8 Group Title
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    |dw:1393563390845:dw|

    • 5 months ago
  2. ganeshie8 Group Title
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    |dw:1393563452971:dw|

    • 5 months ago
  3. ganeshie8 Group Title
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    |dw:1393563500603:dw|

    • 5 months ago
  4. ganeshie8 Group Title
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    b = 5 a = ?

    • 5 months ago
  5. ganeshie8 Group Title
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    if u can find a, u can write the equation of ellipse :- \(\large \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\)

    • 5 months ago
  6. ganeshie8 Group Title
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    any idea how to find "a" ? :)

    • 5 months ago
  7. sarah1017 Group Title
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    How do I find a? Is there a formula I have to follow?

    • 5 months ago
  8. ganeshie8 Group Title
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    u just need to knw how to find an unknown side in a right triangle

    • 5 months ago
  9. sleung Group Title
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    Use the pythagorean theorem.

    • 5 months ago
  10. ganeshie8 Group Title
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    |dw:1393563687257:dw|

    • 5 months ago
  11. ganeshie8 Group Title
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    a^2 = b^2 + c^2 a^2 = 5^2 + 3^2

    • 5 months ago
  12. ganeshie8 Group Title
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    simplify

    • 5 months ago
  13. sarah1017 Group Title
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    a^2=34

    • 5 months ago
  14. ganeshie8 Group Title
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    yes, you want "a" right ?

    • 5 months ago
  15. sarah1017 Group Title
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    Yes. So do I divide 34 by 2?

    • 5 months ago
  16. ganeshie8 Group Title
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    noo, you need to take "square ROOT" both sides

    • 5 months ago
  17. sleung Group Title
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    So \[a=\sqrt{34}\]

    • 5 months ago
  18. sarah1017 Group Title
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    5.83

    • 5 months ago
  19. ganeshie8 Group Title
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    actually im wrong, a^2 is enough as u put it earlier,,,, i see we dont need to find a -.-

    • 5 months ago
  20. ganeshie8 Group Title
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    directly plugin a^2 value in the equation

    • 5 months ago
  21. ganeshie8 Group Title
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    \(\large \frac{x^2}{34} + \frac{y^2}{25} = 1\)

    • 5 months ago
  22. ganeshie8 Group Title
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    ^^final equation of ellipse

    • 5 months ago
  23. sarah1017 Group Title
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    Whoaaa that confused me. So that's the final equation, is the work we did before still correct? Well except the finding a parts?

    • 5 months ago
  24. ganeshie8 Group Title
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    everything is correct, you could even find "a", and plugin the "a" value back into the equaiton

    • 5 months ago
  25. ganeshie8 Group Title
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    but thats just extra unnecessary work

    • 5 months ago
  26. ganeshie8 Group Title
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    when u knw that u will be needing oly "a^2", why to find "a" ?

    • 5 months ago
  27. ganeshie8 Group Title
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    it wont be a mistake to find "a", its just pain to take square root of 34 lol.. .hope u get me :)

    • 5 months ago
  28. sarah1017 Group Title
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    I wasn't too sure how to do this at first so I just went with ya lol. I get it though. Thanks for your help :)

    • 5 months ago
  29. ganeshie8 Group Title
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    np :) u wlc :))

    • 5 months ago
  30. sarah1017 Group Title
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    :-)

    • 5 months ago
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