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What is the standard form of the equation of an ellipse with foci at (+-3,0) and co-vertices at (0,+-5)? Please show all steps!

Mathematics
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Other answers:

b = 5 a = ?
if u can find a, u can write the equation of ellipse :- \(\large \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\)
any idea how to find "a" ? :)
How do I find a? Is there a formula I have to follow?
u just need to knw how to find an unknown side in a right triangle
Use the pythagorean theorem.
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a^2 = b^2 + c^2 a^2 = 5^2 + 3^2
simplify
a^2=34
yes, you want "a" right ?
Yes. So do I divide 34 by 2?
noo, you need to take "square ROOT" both sides
So \[a=\sqrt{34}\]
5.83
actually im wrong, a^2 is enough as u put it earlier,,,, i see we dont need to find a -.-
directly plugin a^2 value in the equation
\(\large \frac{x^2}{34} + \frac{y^2}{25} = 1\)
^^final equation of ellipse
Whoaaa that confused me. So that's the final equation, is the work we did before still correct? Well except the finding a parts?
everything is correct, you could even find "a", and plugin the "a" value back into the equaiton
but thats just extra unnecessary work
when u knw that u will be needing oly "a^2", why to find "a" ?
it wont be a mistake to find "a", its just pain to take square root of 34 lol.. .hope u get me :)
I wasn't too sure how to do this at first so I just went with ya lol. I get it though. Thanks for your help :)
np :) u wlc :))
:-)

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