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anonymous

  • 2 years ago

What is the standard form of the equation of an ellipse with foci at (+-3,0) and co-vertices at (0,+-5)? Please show all steps!

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  1. ganeshie8
    • 2 years ago
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    |dw:1393563390845:dw|

  2. ganeshie8
    • 2 years ago
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    |dw:1393563452971:dw|

  3. ganeshie8
    • 2 years ago
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    |dw:1393563500603:dw|

  4. ganeshie8
    • 2 years ago
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    b = 5 a = ?

  5. ganeshie8
    • 2 years ago
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    if u can find a, u can write the equation of ellipse :- \(\large \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\)

  6. ganeshie8
    • 2 years ago
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    any idea how to find "a" ? :)

  7. anonymous
    • 2 years ago
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    How do I find a? Is there a formula I have to follow?

  8. ganeshie8
    • 2 years ago
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    u just need to knw how to find an unknown side in a right triangle

  9. anonymous
    • 2 years ago
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    Use the pythagorean theorem.

  10. ganeshie8
    • 2 years ago
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    |dw:1393563687257:dw|

  11. ganeshie8
    • 2 years ago
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    a^2 = b^2 + c^2 a^2 = 5^2 + 3^2

  12. ganeshie8
    • 2 years ago
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    simplify

  13. anonymous
    • 2 years ago
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    a^2=34

  14. ganeshie8
    • 2 years ago
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    yes, you want "a" right ?

  15. anonymous
    • 2 years ago
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    Yes. So do I divide 34 by 2?

  16. ganeshie8
    • 2 years ago
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    noo, you need to take "square ROOT" both sides

  17. anonymous
    • 2 years ago
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    So \[a=\sqrt{34}\]

  18. anonymous
    • 2 years ago
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    5.83

  19. ganeshie8
    • 2 years ago
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    actually im wrong, a^2 is enough as u put it earlier,,,, i see we dont need to find a -.-

  20. ganeshie8
    • 2 years ago
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    directly plugin a^2 value in the equation

  21. ganeshie8
    • 2 years ago
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    \(\large \frac{x^2}{34} + \frac{y^2}{25} = 1\)

  22. ganeshie8
    • 2 years ago
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    ^^final equation of ellipse

  23. anonymous
    • 2 years ago
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    Whoaaa that confused me. So that's the final equation, is the work we did before still correct? Well except the finding a parts?

  24. ganeshie8
    • 2 years ago
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    everything is correct, you could even find "a", and plugin the "a" value back into the equaiton

  25. ganeshie8
    • 2 years ago
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    but thats just extra unnecessary work

  26. ganeshie8
    • 2 years ago
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    when u knw that u will be needing oly "a^2", why to find "a" ?

  27. ganeshie8
    • 2 years ago
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    it wont be a mistake to find "a", its just pain to take square root of 34 lol.. .hope u get me :)

  28. anonymous
    • 2 years ago
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    I wasn't too sure how to do this at first so I just went with ya lol. I get it though. Thanks for your help :)

  29. ganeshie8
    • 2 years ago
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    np :) u wlc :))

  30. anonymous
    • 2 years ago
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    :-)

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