anonymous
  • anonymous
6 review questions help please? medal!
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
1. What is the value of h? a. 4 b. 8 sqrt 3 c. 16 d. 8 sqrt 2
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whpalmer4
  • whpalmer4
Okay, you have an isosceles right triangle here, because both of the angles are the same. What does that imply about the associated sides?
anonymous
  • anonymous
They have 2 equal sides and 2 equal angles?

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whpalmer4
  • whpalmer4
Right. So what is the length of the other leg of the triangle?
anonymous
  • anonymous
4 ?
whpalmer4
  • whpalmer4
|dw:1393634970228:dw| What is the value of ???
anonymous
  • anonymous
I'm still not sure .. /:
whpalmer4
  • whpalmer4
come on, we said this was an isosceles triangle, which means two equal angles and two equal sides!
whpalmer4
  • whpalmer4
Doesn't that mean ??? has to be 8?
anonymous
  • anonymous
why would it be 8 ?
anonymous
  • anonymous
sorry I feel stupid >_<
whpalmer4
  • whpalmer4
because it is an isosceles triangle. One of the sides is 8. Another one must be 8 as well, and it can't be the hypotenuse, because the hypotenuse is the longest side.
whpalmer4
  • whpalmer4
it's an isosceles triangle because it has two equal angles. You see that part, right?
anonymous
  • anonymous
ohhhhh ok I understand
whpalmer4
  • whpalmer4
So we can update our drawing: |dw:1393635393884:dw| If the two sides labeled 8 are \(a=8,b=8\) respectively, what is the length of the hypotenuse, \(c\)? Use the Pythagorean theorem
anonymous
  • anonymous
k hold on
anonymous
  • anonymous
its a^2+b^2=c^2 do I add the 45 degrees together to get c? or is the 8?
whpalmer4
  • whpalmer4
The Pythagorean theorem relates only to the lengths of the sides. Angles don't matter (except, of course, that one of them must be 90 degrees for it to be a right triangle).
whpalmer4
  • whpalmer4
\[a^2+b^2=c^2\]\[8^2+8^2=c^2\]\[2*8^2 = c^2\]Take the square root of both sides:\[\sqrt{2*8^2} = \sqrt{c^2}\]Simplify\[8\sqrt{2} = c\] If you have a \(45^\circ/45^\circ/90^\circ\) triangle such as this one, the side lengths are always in the ratio \(1:1:\sqrt{2}\)
anonymous
  • anonymous
is that the way you would do it for this kind of triangle too ?
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anonymous
  • anonymous
@whpalmer4
whpalmer4
  • whpalmer4
I don't understand your question.
anonymous
  • anonymous
Use the Pythagorean theorem
whpalmer4
  • whpalmer4
Well, yes, if you know 2 sides in a right triangle, you can use the PT to find the 3rd side.
anonymous
  • anonymous
okay ty c:
whpalmer4
  • whpalmer4
you're welcome

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