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DrPepperx3
6 review questions help please? medal!
1. What is the value of h? a. 4 b. 8 sqrt 3 c. 16 d. 8 sqrt 2
Okay, you have an isosceles right triangle here, because both of the angles are the same. What does that imply about the associated sides?
They have 2 equal sides and 2 equal angles?
Right. So what is the length of the other leg of the triangle?
|dw:1393634970228:dw| What is the value of ???
I'm still not sure .. /:
come on, we said this was an isosceles triangle, which means two equal angles and two equal sides!
Doesn't that mean ??? has to be 8?
sorry I feel stupid >_<
because it is an isosceles triangle. One of the sides is 8. Another one must be 8 as well, and it can't be the hypotenuse, because the hypotenuse is the longest side.
it's an isosceles triangle because it has two equal angles. You see that part, right?
ohhhhh ok I understand
So we can update our drawing: |dw:1393635393884:dw| If the two sides labeled 8 are \(a=8,b=8\) respectively, what is the length of the hypotenuse, \(c\)? Use the Pythagorean theorem
its a^2+b^2=c^2 do I add the 45 degrees together to get c? or is the 8?
The Pythagorean theorem relates only to the lengths of the sides. Angles don't matter (except, of course, that one of them must be 90 degrees for it to be a right triangle).
\[a^2+b^2=c^2\]\[8^2+8^2=c^2\]\[2*8^2 = c^2\]Take the square root of both sides:\[\sqrt{2*8^2} = \sqrt{c^2}\]Simplify\[8\sqrt{2} = c\] If you have a \(45^\circ/45^\circ/90^\circ\) triangle such as this one, the side lengths are always in the ratio \(1:1:\sqrt{2}\)
is that the way you would do it for this kind of triangle too ?
I don't understand your question.
Use the Pythagorean theorem
Well, yes, if you know 2 sides in a right triangle, you can use the PT to find the 3rd side.