A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Open

jdoe0001
 9 months ago
Best ResponseYou've already chosen the best response.0\(\bf sin (2x) =\cfrac{1}{2}\quad \textit{take }sin^{1} \\ \quad \\ sin^{1}[sin ({\color{red}{ 2x}})]=sin^{1}\left(\frac{1}{2}\right)\implies {\color{red}{ 2x}}=sin^{1}\left(\frac{1}{2}\right)\) solve for "x"

kb6
 9 months ago
Best ResponseYou've already chosen the best response.0It says to solve the equation on the interval 0<x<2pi

jdoe0001
 9 months ago
Best ResponseYou've already chosen the best response.0yes so... what did you get for "x"?

surjithayer
 9 months ago
Best ResponseYou've already chosen the best response.0\[\sin 2x=\frac{ 1 }{ 2 }=\sin \frac{ \pi }{6 }=\sin \left( \pi+\frac{ \pi }{6 } \right),\sin \left( 2\pi\frac{ \pi }{ 6 } \right),\sin \left( 2\pi+\pi+\frac{ \pi }{ 6 } \right),\] \[\sin \left( 2\pi+2\pi\frac{ \pi }{6 } \right)\] 2x=? x=?
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.