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xuvaze

  • one year ago

Write a possible explicit rule for the nth term: 1/2, 1/4, 1/6, 1/8, 1/10

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  1. xuvaze
    • one year ago
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    Any help would be greatly appreciate! I have been stuck on this problem for about an hour. It's the last one and the most difficult! First differences are not constant, neither are the second differences or ratios. I'm confused as to how I'm supposed to tackle this problem.

  2. tkhunny
    • one year ago
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    If it were me, I would write the Prime Factorization of all the Denominators. This may lead to something obvious.

  3. xuvaze
    • one year ago
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    @tkhunny - Am I supposed to figure out the least common denominator between all of them?

  4. myininaya
    • one year ago
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    Notice the denominators are all even.

  5. sourwing
    • one year ago
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    a(n) = 1/(2n)

  6. xuvaze
    • one year ago
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    @tkhunny - 1/2: 2 x 1 , 1/4: 2 x 2 , 1/6,: 3 x 2, 1/8: 4 x 2; 2 x 2 x 2, 1/10: 5 x 2 I do see a pattern here! :)

  7. xuvaze
    • one year ago
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    @myininaya thanks for the hint! @sourwing - may I ask how you got that answer?

  8. sourwing
    • one year ago
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    well, 2 = 2*1 4 = 3*2 6 = 2*n ... so 1/(2n) there's not much else I can say except the pattern is obvious

  9. tkhunny
    • one year ago
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    2*1 2*2 2*3 2*4 2*5 Are you SURE you don't see a pattern?

  10. xuvaze
    • one year ago
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    @sourwing - that's what I thought. I was just making sure. :p @tkhunny - Yes, I do see a pattern. I already said that I did!

  11. xuvaze
    • one year ago
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    Thanks for the help guys! I really appreciate it. :)

  12. jdoe0001
    • one year ago
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    eheheh

  13. tkhunny
    • one year ago
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    My b. Didn't read the whole thread. :-)

  14. jdoe0001
    • one year ago
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    the file is not relevant btw =)

  15. jdoe0001
    • one year ago
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    just putting up a file for a quick link, is all =)

  16. xuvaze
    • one year ago
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    @jdoe0001 - I suggest using imgur for that. I don't want you to get in trouble for posting irrelevant information on an already closed question!

  17. jdoe0001
    • one year ago
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    indeed

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