anonymous
  • anonymous
Write a possible explicit rule for the nth term: 1/2, 1/4, 1/6, 1/8, 1/10
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
Any help would be greatly appreciate! I have been stuck on this problem for about an hour. It's the last one and the most difficult! First differences are not constant, neither are the second differences or ratios. I'm confused as to how I'm supposed to tackle this problem.
tkhunny
  • tkhunny
If it were me, I would write the Prime Factorization of all the Denominators. This may lead to something obvious.
anonymous
  • anonymous
@tkhunny - Am I supposed to figure out the least common denominator between all of them?

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myininaya
  • myininaya
Notice the denominators are all even.
anonymous
  • anonymous
a(n) = 1/(2n)
anonymous
  • anonymous
@tkhunny - 1/2: 2 x 1 , 1/4: 2 x 2 , 1/6,: 3 x 2, 1/8: 4 x 2; 2 x 2 x 2, 1/10: 5 x 2 I do see a pattern here! :)
anonymous
  • anonymous
@myininaya thanks for the hint! @sourwing - may I ask how you got that answer?
anonymous
  • anonymous
well, 2 = 2*1 4 = 3*2 6 = 2*n ... so 1/(2n) there's not much else I can say except the pattern is obvious
tkhunny
  • tkhunny
2*1 2*2 2*3 2*4 2*5 Are you SURE you don't see a pattern?
anonymous
  • anonymous
@sourwing - that's what I thought. I was just making sure. :p @tkhunny - Yes, I do see a pattern. I already said that I did!
anonymous
  • anonymous
Thanks for the help guys! I really appreciate it. :)
jdoe0001
  • jdoe0001
eheheh
tkhunny
  • tkhunny
My b. Didn't read the whole thread. :-)
jdoe0001
  • jdoe0001
the file is not relevant btw =)
jdoe0001
  • jdoe0001
just putting up a file for a quick link, is all =)
anonymous
  • anonymous
@jdoe0001 - I suggest using imgur for that. I don't want you to get in trouble for posting irrelevant information on an already closed question!
jdoe0001
  • jdoe0001
indeed

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