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music101
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Convert the polar equation to rectangular form and identify the graph.
r= 7/ (2cosΘ+5sinΘ)
 7 months ago
 7 months ago
music101 Group Title
Convert the polar equation to rectangular form and identify the graph. r= 7/ (2cosΘ+5sinΘ)
 7 months ago
 7 months ago

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music101 Group TitleBest ResponseYou've already chosen the best response.0
dw:1393722700861:dw
 7 months ago

sourwing Group TitleBest ResponseYou've already chosen the best response.0
y = r sin(theta) x = r cos(theta) x^2 + y^2 = r^2 plug and chug
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
yea so how would i plug it in
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
cuz i did this last week and i kinda forgot sorry
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Try getting your cos and sin with r over there by multiplying both sides by 2cos(theta)+5sin(theta)
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
okay. i did that
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
So you have: \[2rcos(\theta)+5rsin(\theta)=7 ?\]
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
why would you put r w/ each one of the terms isnt there just 1?
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[r=\frac{7}{2\cos(\theta)+5 \sin(\theta)} => r(2\cos(\theta)+5 \sin(\theta))=7\] Distributive property!
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
oh ok i gotchu
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
you should have it from here. Use the equations sour gave you.
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
thannk you(:
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
what if the question's like r= 3sinΘ ?
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Try multiplying r on both sides recall rsin(theta)=y and r^2=x^2+y^2
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
hmm ok...
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
so r^2= 3rsinΘ?
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
right so now you are able to replace rsin(theta) with y and r^2 with x^2+y^2
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
then youd have?
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
the square root of that right?
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
just do exactly what I said replace r sin(theta) with y replace r^2 with x^2+y^2
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
i did tht
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
you are done what else do you want?
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
is tht my final answer
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
putting an equation in terms of just x and y ( or just x or just y) is called a cartesian equation if that was the directions to just right as a cartesian equation then you are done
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
right, sorry. i missed a problem on my homework it was r= 2sinΘ4cosΘ
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
multiply both sides by r
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
do you square both sides 1st
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
thts what i emant
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
replace r^2 with x^2+y^2 replace r sin(theta) with y replace r cos(theta) with x
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
ok i did that: x^2+y^2= 2y4x
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
yep. :) that is right you wrote the poloar equation as a cartesian equation if that is all the directions said to do then you are done.
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
do you stop there
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
aand i missed r= 3+3cosΘ
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
so i multiplied both sides by r 1st
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
and got x^2+y^2=3r +3x but dont i need to get rid of the r?
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
you could subtract both sides by 3x giving you \[x^2+y^23x=3r \] then square both sides and replace the r^2 with x^2+y^2
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
why square both sides?
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
I just prefer my answer without radicals and me squaring both sides will allow me to write my answer without radicals
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
so what would be final answer then
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
what if you with what I was saying take my equation and then square both sides and then replace the r^2 with x^2+y^2 you will have your final answer
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
yeah but when you square the whole left side you get x^4+y^49x^2 = 3x^2+y^2?
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[(x^2+y^23x)^2=(3r)^2 \] the us what you get when you square both sides your equation is not equivalent to that you squared each term sorta but not really it is whatever you do to one side of equation you can do to the other and the equation still holds
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[\text {recall law of exponents} (3r)^2=3^2r^2=9r^2=9(x^2+y^2) \]
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
im not following are you saying keep left side just squared in parentheses?
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
It is easier than multiplying it out, don't you think?
 7 months ago

music101 Group TitleBest ResponseYou've already chosen the best response.0
yes. so only change right side. like substitue
 7 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
You can multiply it out if you want. Just do it correctly, but the if the directions just say write as a rectangular (aka cartesian equation) than you are done. If the left hand side was already in terms of x and y. r^2 was the only thing that needed to be converted.
 7 months ago
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