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anonymous
 2 years ago
Convert the polar equation to rectangular form and identify the graph.
r= 7/ (2cosΘ+5sinΘ)
anonymous
 2 years ago
Convert the polar equation to rectangular form and identify the graph. r= 7/ (2cosΘ+5sinΘ)

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1393722700861:dw

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0y = r sin(theta) x = r cos(theta) x^2 + y^2 = r^2 plug and chug

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0yea so how would i plug it in

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0cuz i did this last week and i kinda forgot sorry

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1Try getting your cos and sin with r over there by multiplying both sides by 2cos(theta)+5sin(theta)

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1So you have: \[2rcos(\theta)+5rsin(\theta)=7 ?\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0why would you put r w/ each one of the terms isnt there just 1?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1\[r=\frac{7}{2\cos(\theta)+5 \sin(\theta)} => r(2\cos(\theta)+5 \sin(\theta))=7\] Distributive property!

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1you should have it from here. Use the equations sour gave you.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0what if the question's like r= 3sinΘ ?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1Try multiplying r on both sides recall rsin(theta)=y and r^2=x^2+y^2

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1right so now you are able to replace rsin(theta) with y and r^2 with x^2+y^2

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0the square root of that right?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1just do exactly what I said replace r sin(theta) with y replace r^2 with x^2+y^2

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1you are done what else do you want?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0is tht my final answer

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1putting an equation in terms of just x and y ( or just x or just y) is called a cartesian equation if that was the directions to just right as a cartesian equation then you are done

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0right, sorry. i missed a problem on my homework it was r= 2sinΘ4cosΘ

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1multiply both sides by r

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0do you square both sides 1st

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1replace r^2 with x^2+y^2 replace r sin(theta) with y replace r cos(theta) with x

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0ok i did that: x^2+y^2= 2y4x

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1yep. :) that is right you wrote the poloar equation as a cartesian equation if that is all the directions said to do then you are done.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0aand i missed r= 3+3cosΘ

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0so i multiplied both sides by r 1st

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0and got x^2+y^2=3r +3x but dont i need to get rid of the r?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1you could subtract both sides by 3x giving you \[x^2+y^23x=3r \] then square both sides and replace the r^2 with x^2+y^2

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0why square both sides?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1I just prefer my answer without radicals and me squaring both sides will allow me to write my answer without radicals

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0so what would be final answer then

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1what if you with what I was saying take my equation and then square both sides and then replace the r^2 with x^2+y^2 you will have your final answer

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0yeah but when you square the whole left side you get x^4+y^49x^2 = 3x^2+y^2?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1\[(x^2+y^23x)^2=(3r)^2 \] the us what you get when you square both sides your equation is not equivalent to that you squared each term sorta but not really it is whatever you do to one side of equation you can do to the other and the equation still holds

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1\[\text {recall law of exponents} (3r)^2=3^2r^2=9r^2=9(x^2+y^2) \]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0im not following are you saying keep left side just squared in parentheses?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1It is easier than multiplying it out, don't you think?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0yes. so only change right side. like substitue

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1You can multiply it out if you want. Just do it correctly, but the if the directions just say write as a rectangular (aka cartesian equation) than you are done. If the left hand side was already in terms of x and y. r^2 was the only thing that needed to be converted.
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