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salparadise64

  • one year ago

need help proving reduction formula for calc

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  1. salparadise64
    • one year ago
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    please...

  2. salparadise64
    • one year ago
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    @roadjester

  3. roadjester
    • one year ago
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    who's the author of your book?

  4. roadjester
    • one year ago
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    Stewart?

  5. salparadise64
    • one year ago
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    james stewart

  6. roadjester
    • one year ago
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    What edition?

  7. salparadise64
    • one year ago
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    calculus early transcendental 7th E

  8. salparadise64
    • one year ago
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    @abb0t

  9. roadjester
    • one year ago
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    Damn, I've got Calculus 6th oh well

  10. roadjester
    • one year ago
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    Let me think; haven't done calc in a while

  11. salparadise64
    • one year ago
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    hmmmmm

  12. roadjester
    • one year ago
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    I'm just gonna BS this, maybe something will come to me. \(\int{tan^nxdx=\int tan^{n-1}}(x) tan(x)dx\)

  13. salparadise64
    • one year ago
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    pg 469 section 7.1 #53

  14. salparadise64
    • one year ago
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    yeah, i have the solution manual too, i was hoping someone would be able to explain it.

  15. roadjester
    • one year ago
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    oookkaay; I think the solution is self-explanatory...

  16. myininaya
    • one year ago
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    \[\int\limits_{}^{}\tan^n dx=\int\limits_{}^{}\tan^{n-2}(x)\tan^2(x) dx=\int\limits_{}^{}\tan^{n-2}(x)(\sec^2(x)-1) dx\] \[=\int\limits_{}^{}\tan^{n-2}(x)\sec^2(x)-\int\limits_{}^{}\tan^{n-2}(x) dx\] do a sub let u=tan(x) du=sec^2(x) dx and you will see you are almost done

  17. salparadise64
    • one year ago
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    @myininaya thank you!

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