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salparadise64 Group TitleBest ResponseYou've already chosen the best response.0
please...
 9 months ago

salparadise64 Group TitleBest ResponseYou've already chosen the best response.0
@roadjester
 9 months ago

roadjester Group TitleBest ResponseYou've already chosen the best response.1
who's the author of your book?
 9 months ago

roadjester Group TitleBest ResponseYou've already chosen the best response.1
Stewart?
 9 months ago

salparadise64 Group TitleBest ResponseYou've already chosen the best response.0
james stewart
 9 months ago

roadjester Group TitleBest ResponseYou've already chosen the best response.1
What edition?
 9 months ago

salparadise64 Group TitleBest ResponseYou've already chosen the best response.0
calculus early transcendental 7th E
 9 months ago

salparadise64 Group TitleBest ResponseYou've already chosen the best response.0
@abb0t
 9 months ago

roadjester Group TitleBest ResponseYou've already chosen the best response.1
Damn, I've got Calculus 6th oh well
 9 months ago

roadjester Group TitleBest ResponseYou've already chosen the best response.1
Let me think; haven't done calc in a while
 9 months ago

salparadise64 Group TitleBest ResponseYou've already chosen the best response.0
hmmmmm
 9 months ago

roadjester Group TitleBest ResponseYou've already chosen the best response.1
I'm just gonna BS this, maybe something will come to me. \(\int{tan^nxdx=\int tan^{n1}}(x) tan(x)dx\)
 9 months ago

salparadise64 Group TitleBest ResponseYou've already chosen the best response.0
pg 469 section 7.1 #53
 9 months ago

salparadise64 Group TitleBest ResponseYou've already chosen the best response.0
yeah, i have the solution manual too, i was hoping someone would be able to explain it.
 9 months ago

roadjester Group TitleBest ResponseYou've already chosen the best response.1
oookkaay; I think the solution is selfexplanatory...
 9 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
\[\int\limits_{}^{}\tan^n dx=\int\limits_{}^{}\tan^{n2}(x)\tan^2(x) dx=\int\limits_{}^{}\tan^{n2}(x)(\sec^2(x)1) dx\] \[=\int\limits_{}^{}\tan^{n2}(x)\sec^2(x)\int\limits_{}^{}\tan^{n2}(x) dx\] do a sub let u=tan(x) du=sec^2(x) dx and you will see you are almost done
 9 months ago

salparadise64 Group TitleBest ResponseYou've already chosen the best response.0
@myininaya thank you!
 9 months ago
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