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mony01
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits \frac{ x ^{2} +x+1}{ (x ^{2}+1)^{2} }dx\]

wio
 one year ago
Best ResponseYou've already chosen the best response.0Play around with the fraction.

wio
 one year ago
Best ResponseYou've already chosen the best response.0Maybe partial fraction decomposition

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1did you try a trig sub i think that would work just fine

mony01
 one year ago
Best ResponseYou've already chosen the best response.0you think i can try sin?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1I think you can try tan

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1the hint was the x^2+1 on bottom

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1tan^2(theta)+1=sec^2(theta)

mony01
 one year ago
Best ResponseYou've already chosen the best response.0would the set up be integral x^2+x+1/sex^2 theta

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1well you have to replace all the x's and the dx

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1and also you are leaving off the square on bottom

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1\[x=\tan(\theta) => dx=\sec^2(\theta) d \theta \] Replace all the x's with tan(theta) Replace the dx with sec^2(theta) d theta

mony01
 one year ago
Best ResponseYou've already chosen the best response.0is it integral tan^2theta+tan theta+1/sec^2 theta d (theta)

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1If I think what you wrote is what I think then yes. You mean the following I assume: integral of (tan^2(theta)+tan(theta)+1)/sec^2(theta) d(theta)

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{}^{}\frac{\tan^2(\theta)}{\sec^2(\theta)} d \theta +\int\limits_{}^{}\frac{\tan(\theta)}{\sec^2(\theta)} d \theta +\int\limits_{}^{} \frac{1}{\sec^2(\theta) }d \theta \]

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Look at them three separately

gorv
 one year ago
Best ResponseYou've already chosen the best response.4\[\int\limits_{}^{}(\frac{ x^2+1 }{ (x^2+1)^2 } +\frac{ x }{ (x^2+1)^2 })*dx\]

gorv
 one year ago
Best ResponseYou've already chosen the best response.4\[\int\limits_{}^{}\frac{ dx }{ x^2+1 } +\int\limits_{}^{}\frac{ x }{ (x^2+1)^2 }\]

gorv
 one year ago
Best ResponseYou've already chosen the best response.4first one is standard formula

mony01
 one year ago
Best ResponseYou've already chosen the best response.0how can i figure out the answer?

gorv
 one year ago
Best ResponseYou've already chosen the best response.4\[\int\limits_{}^{}\frac{ x }{ (x^2+1)^2 } *dx\] for this x^2+1=t 2xdx=dt xdx=dt/2

gorv
 one year ago
Best ResponseYou've already chosen the best response.4\[\int\limits_{}^{} \frac{ dt }{ 2*t^2 }\]

gorv
 one year ago
Best ResponseYou've already chosen the best response.4\[\int\limits_{}^{}\frac{ dx }{ x^2+1 } +\int\limits_{}^{}\frac{ dt }{ 2t^2 }\]

mony01
 one year ago
Best ResponseYou've already chosen the best response.0is it sec^2 (theta)/2(x^2+1)^2

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1I do like gorv's way. But either way is fine. gorv's is simpler though.

gorv
 one year ago
Best ResponseYou've already chosen the best response.4actual its less calculative...both ways anns will be same

mony01
 one year ago
Best ResponseYou've already chosen the best response.0how can i solve the rest of it?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1What question on what part do you have?

mony01
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits \frac{ dx }{ x ^{2}+1}+\int\limits \frac{ dt }{ 2t ^{2} }\]

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1the first integral is just remembering that it is acran(x) the second one 1/2 is a constant multiple and you should know how to integrate t^(2) at this point in calculus

mony01
 one year ago
Best ResponseYou've already chosen the best response.0is the answer arctan(x)1/2(x^2+1)+C

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Yes that's right you mean arctan(x) 1/[2(x^2+1)] +C good job
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