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mony01
 9 months ago
Best ResponseYou've already chosen the best response.0\[\int\limits \frac{ x ^{2} +x+1}{ (x ^{2}+1)^{2} }dx\]

wio
 9 months ago
Best ResponseYou've already chosen the best response.0Play around with the fraction.

wio
 9 months ago
Best ResponseYou've already chosen the best response.0Maybe partial fraction decomposition

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1did you try a trig sub i think that would work just fine

mony01
 9 months ago
Best ResponseYou've already chosen the best response.0you think i can try sin?

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1I think you can try tan

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1the hint was the x^2+1 on bottom

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1tan^2(theta)+1=sec^2(theta)

mony01
 9 months ago
Best ResponseYou've already chosen the best response.0would the set up be integral x^2+x+1/sex^2 theta

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1well you have to replace all the x's and the dx

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1and also you are leaving off the square on bottom

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1\[x=\tan(\theta) => dx=\sec^2(\theta) d \theta \] Replace all the x's with tan(theta) Replace the dx with sec^2(theta) d theta

mony01
 9 months ago
Best ResponseYou've already chosen the best response.0is it integral tan^2theta+tan theta+1/sec^2 theta d (theta)

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1If I think what you wrote is what I think then yes. You mean the following I assume: integral of (tan^2(theta)+tan(theta)+1)/sec^2(theta) d(theta)

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{}^{}\frac{\tan^2(\theta)}{\sec^2(\theta)} d \theta +\int\limits_{}^{}\frac{\tan(\theta)}{\sec^2(\theta)} d \theta +\int\limits_{}^{} \frac{1}{\sec^2(\theta) }d \theta \]

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1Look at them three separately

gorv
 9 months ago
Best ResponseYou've already chosen the best response.4\[\int\limits_{}^{}(\frac{ x^2+1 }{ (x^2+1)^2 } +\frac{ x }{ (x^2+1)^2 })*dx\]

gorv
 9 months ago
Best ResponseYou've already chosen the best response.4\[\int\limits_{}^{}\frac{ dx }{ x^2+1 } +\int\limits_{}^{}\frac{ x }{ (x^2+1)^2 }\]

gorv
 9 months ago
Best ResponseYou've already chosen the best response.4first one is standard formula

mony01
 9 months ago
Best ResponseYou've already chosen the best response.0how can i figure out the answer?

gorv
 9 months ago
Best ResponseYou've already chosen the best response.4\[\int\limits_{}^{}\frac{ x }{ (x^2+1)^2 } *dx\] for this x^2+1=t 2xdx=dt xdx=dt/2

gorv
 9 months ago
Best ResponseYou've already chosen the best response.4\[\int\limits_{}^{} \frac{ dt }{ 2*t^2 }\]

gorv
 9 months ago
Best ResponseYou've already chosen the best response.4\[\int\limits_{}^{}\frac{ dx }{ x^2+1 } +\int\limits_{}^{}\frac{ dt }{ 2t^2 }\]

mony01
 9 months ago
Best ResponseYou've already chosen the best response.0is it sec^2 (theta)/2(x^2+1)^2

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1I do like gorv's way. But either way is fine. gorv's is simpler though.

gorv
 9 months ago
Best ResponseYou've already chosen the best response.4actual its less calculative...both ways anns will be same

mony01
 9 months ago
Best ResponseYou've already chosen the best response.0how can i solve the rest of it?

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1What question on what part do you have?

mony01
 9 months ago
Best ResponseYou've already chosen the best response.0\[\int\limits \frac{ dx }{ x ^{2}+1}+\int\limits \frac{ dt }{ 2t ^{2} }\]

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1the first integral is just remembering that it is acran(x) the second one 1/2 is a constant multiple and you should know how to integrate t^(2) at this point in calculus

mony01
 9 months ago
Best ResponseYou've already chosen the best response.0is the answer arctan(x)1/2(x^2+1)+C

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1Yes that's right you mean arctan(x) 1/[2(x^2+1)] +C good job
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