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\[\cos2\theta=-\frac{ \sqrt{3} }{ 2 }\]

\[2\theta= \pi+ \cos^-1\frac{ \sqrt{3} }{ 2 } or =\pi-\cos^-1\frac{ \sqrt{3} }{ 2 }\]

If I follow correctly, then that means the solution set will only be {5π/12 , 17π/12}, correct?