mony01
anybody know how to do this integral?
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mony01
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\[\int\limits \frac{ x ^{2} +1}{ (x-3)(x-2)^{2} }dx\]
myininaya
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you can try partial fractions
mony01
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im stuck in the part where you have to find A,B, and C
myininaya
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Can I see what you have so far?
mony01
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x^2+1=A(x-2)^2+B(x-2)(x-3)+C(x-3)
myininaya
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You can find C pretty fast by letting x be 2
myininaya
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You can find A pretty fast also by letting x be 3
myininaya
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You have two unknown values which it leaves you with the one, B.
You can replace A with whatever you found and replace C with whatever you found and then use any value for x besides 2 or 3 to find B
mony01
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is C=-5 and A=10
myininaya
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yep
mony01
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B=-9 when x=1
myininaya
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yep
mony01
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when putting it all together how can i simplify -5/(x-2)^2?
myininaya
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You mean integrate it?
myininaya
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how would you integrate -5/u^2 with respect to u?
mony01
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yea
hartnn
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where are you stuck now?