anybody know how to do this integral?

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anybody know how to do this integral?

Mathematics
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\[\int\limits \frac{ x ^{2} +1}{ (x-3)(x-2)^{2} }dx\]
you can try partial fractions
im stuck in the part where you have to find A,B, and C

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Other answers:

Can I see what you have so far?
x^2+1=A(x-2)^2+B(x-2)(x-3)+C(x-3)
You can find C pretty fast by letting x be 2
You can find A pretty fast also by letting x be 3
You have two unknown values which it leaves you with the one, B. You can replace A with whatever you found and replace C with whatever you found and then use any value for x besides 2 or 3 to find B
is C=-5 and A=10
yep
B=-9 when x=1
yep
when putting it all together how can i simplify -5/(x-2)^2?
You mean integrate it?
how would you integrate -5/u^2 with respect to u?
yea
where are you stuck now?

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