Here's the question you clicked on:
Maymien
find dx/dy if X<sup>3</sup> +x tan<sup>-1</sup>(y)=e <sup>y</sup>
I can't read this very well.
what do the sup's mean?
do you mean x^3+arctan(y)=e^y?
its mean quadrate, yes, please help its for my brother math homework
Do you know power rule? And I guess we are looking at x as a function of y. \[(x^n)'=nx^{n-1} \frac{dx}{dy}\] \[(\arctan(x))'=\frac{1}{1+x^2} \cdot \frac{dx}{dy}\] \[(e^x)'=e^x \frac{dx}{dy} \] I hope that helps you and your brother get started.
thank you so much, we will try get started