Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

raechelvictoria

  • 2 years ago

A rectangular swimming pool has the following dimensions: length 30 m, width 15 m, depth 3 m on the adult side and 1 m at the children side. If water is pumped into the pool at the rate of 15 m^3/min, how fast is the water rising when it is 2 meters deep at the adult side?

  • This Question is Closed
  1. raechelvictoria
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @hartnn Please help :(

  2. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1393758941737:dw|

  3. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1393759122478:dw| Volume of water as of now = area of triangle * depth

  4. ganeshie8
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \(\large \frac{dV}{dt} = 15\)

  5. ganeshie8
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    using the diagram above, setup an equation for volume

  6. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy