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hamandbones
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I need to find the limit as x goes to 9. I must use factoring. How can I factor?
((x^(3/2))27) / x9
 5 months ago
 5 months ago
hamandbones Group Title
I need to find the limit as x goes to 9. I must use factoring. How can I factor? ((x^(3/2))27) / x9
 5 months ago
 5 months ago

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ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
use a^3b^3 formula for numerator
 5 months ago

alekos Group TitleBest ResponseYou've already chosen the best response.0
not sure if that's going to do the trick we get on the top line (sqrtx 3)(x+3sqrtx +9)
 5 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
bottom also we can factor : \( x 9 = (\sqrt{x})^2  3^2\)
 5 months ago

alekos Group TitleBest ResponseYou've already chosen the best response.0
yes of course!
 5 months ago

alekos Group TitleBest ResponseYou've already chosen the best response.0
over to you ham and bones
 5 months ago

hamandbones Group TitleBest ResponseYou've already chosen the best response.0
I don't think this solves the problem. I am trying to find the limit as x goes to 9. If you put in 9 for x, the denominator is still 0 or undefined. Something must be cancelled off so you can plug 9 into for x and solve.
 5 months ago

alekos Group TitleBest ResponseYou've already chosen the best response.0
Yes it does. Top line (sqrtx 3)(x+3sqrtx+9) Bottom line (sqrtx+3)(sqrtx3)
 5 months ago
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