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hamandbones
 one year ago
I need to find the limit as x goes to 9. I must use factoring. How can I factor?
((x^(3/2))27) / x9
hamandbones
 one year ago
I need to find the limit as x goes to 9. I must use factoring. How can I factor? ((x^(3/2))27) / x9

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ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0use a^3b^3 formula for numerator

alekos
 one year ago
Best ResponseYou've already chosen the best response.0not sure if that's going to do the trick we get on the top line (sqrtx 3)(x+3sqrtx +9)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0bottom also we can factor : \( x 9 = (\sqrt{x})^2  3^2\)

alekos
 one year ago
Best ResponseYou've already chosen the best response.0over to you ham and bones

hamandbones
 one year ago
Best ResponseYou've already chosen the best response.0I don't think this solves the problem. I am trying to find the limit as x goes to 9. If you put in 9 for x, the denominator is still 0 or undefined. Something must be cancelled off so you can plug 9 into for x and solve.

alekos
 one year ago
Best ResponseYou've already chosen the best response.0Yes it does. Top line (sqrtx 3)(x+3sqrtx+9) Bottom line (sqrtx+3)(sqrtx3)
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