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hamandbones Group Title

I need to find the limit as x goes to 9. I must use factoring. How can I factor? ((x^(3/2))-27) / x-9

  • 6 months ago
  • 6 months ago

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  1. ganeshie8 Group Title
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    use a^3-b^3 formula for numerator

    • 6 months ago
  2. alekos Group Title
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    not sure if that's going to do the trick we get on the top line (sqrtx -3)(x+3sqrtx +9)

    • 6 months ago
  3. ganeshie8 Group Title
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    bottom also we can factor : \( x- 9 = (\sqrt{x})^2 - 3^2\)

    • 6 months ago
  4. alekos Group Title
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    yes of course!

    • 6 months ago
  5. alekos Group Title
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    over to you ham and bones

    • 6 months ago
  6. hamandbones Group Title
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    I don't think this solves the problem. I am trying to find the limit as x goes to 9. If you put in 9 for x, the denominator is still 0 or undefined. Something must be cancelled off so you can plug 9 into for x and solve.

    • 6 months ago
  7. alekos Group Title
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    Yes it does. Top line (sqrtx -3)(x+3sqrtx+9) Bottom line (sqrtx+3)(sqrtx-3)

    • 6 months ago
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