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hamandbones

  • 2 years ago

I need to find the limit as x goes to 9. I must use factoring. How can I factor? ((x^(3/2))-27) / x-9

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  1. ganeshie8
    • 2 years ago
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    use a^3-b^3 formula for numerator

  2. alekos
    • 2 years ago
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    not sure if that's going to do the trick we get on the top line (sqrtx -3)(x+3sqrtx +9)

  3. ganeshie8
    • 2 years ago
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    bottom also we can factor : \( x- 9 = (\sqrt{x})^2 - 3^2\)

  4. alekos
    • 2 years ago
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    yes of course!

  5. alekos
    • 2 years ago
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    over to you ham and bones

  6. hamandbones
    • 2 years ago
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    I don't think this solves the problem. I am trying to find the limit as x goes to 9. If you put in 9 for x, the denominator is still 0 or undefined. Something must be cancelled off so you can plug 9 into for x and solve.

  7. alekos
    • 2 years ago
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    Yes it does. Top line (sqrtx -3)(x+3sqrtx+9) Bottom line (sqrtx+3)(sqrtx-3)

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