hamandbones one year ago I need to find the limit as x goes to 9. I must use factoring. How can I factor? ((x^(3/2))-27) / x-9

1. ganeshie8

use a^3-b^3 formula for numerator

2. alekos

not sure if that's going to do the trick we get on the top line (sqrtx -3)(x+3sqrtx +9)

3. ganeshie8

bottom also we can factor : $$x- 9 = (\sqrt{x})^2 - 3^2$$

4. alekos

yes of course!

5. alekos

over to you ham and bones

6. hamandbones

I don't think this solves the problem. I am trying to find the limit as x goes to 9. If you put in 9 for x, the denominator is still 0 or undefined. Something must be cancelled off so you can plug 9 into for x and solve.

7. alekos

Yes it does. Top line (sqrtx -3)(x+3sqrtx+9) Bottom line (sqrtx+3)(sqrtx-3)