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I need to find the limit as x goes to 9. I must use factoring. How can I factor? ((x^(3/2))-27) / x-9

Mathematics
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use a^3-b^3 formula for numerator
not sure if that's going to do the trick we get on the top line (sqrtx -3)(x+3sqrtx +9)
bottom also we can factor : \( x- 9 = (\sqrt{x})^2 - 3^2\)

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yes of course!
over to you ham and bones
I don't think this solves the problem. I am trying to find the limit as x goes to 9. If you put in 9 for x, the denominator is still 0 or undefined. Something must be cancelled off so you can plug 9 into for x and solve.
Yes it does. Top line (sqrtx -3)(x+3sqrtx+9) Bottom line (sqrtx+3)(sqrtx-3)

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