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arneswe

  • 2 years ago

y=ln(2x*e^-x)

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  1. louieg888
    • 2 years ago
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    yes. That is a function. What do you want to do? Integrate? Derivative? Sum?

  2. arneswe
    • 2 years ago
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    Derivative

  3. AndrewLentz
    • 2 years ago
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    derivative of a natural log is 1/u * du/dx. so in this case its 1/(2x*e^-x) * (2e^-x - 2xe^-x) simplified form is dy/dx = (1-x)/x

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