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i think its correct not solved but just what u wrote

it might be 12+(x-1)

It makes no difference because at some point you'll have to get rid of the brackets :L

your last step is wrong..

I think u should multiply
(x/12+x) *(x-1/11+x)=5/51
like this

Hence probability of both happening is the product, not sum!

\[P(A and B) = P(A).P(B provided A has happened)\]

Oh, I got ye, I'll try it that way

yeh Mashy is correct , multiply the terms :)

\[\frac{ x ^{2}-x}{ x ^{2}+23x+132 }=\frac{ 5 }{ 51 }\]
...
...
...
Leads me to
x1=6.18 and
x2=-2.57

try solving again

\[51x^{2}-51x=5x ^{2}+115x+660\]
\[46x ^{2}-166x-660=0\]
\[x _{1}=6.18 >----< x _{2}==2.57\]

Sorry

your quadratic equation is correct...your final solution is not

Wrong typing in calculator, I got 6, thanks guys! :)