Can someone pleassssse help me with this problem? :) Solve for x. Enter only a number. 3 = log8 + 3logx HINT: If loga = 3, then a = 103.

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Can someone pleassssse help me with this problem? :) Solve for x. Enter only a number. 3 = log8 + 3logx HINT: If loga = 3, then a = 103.

Mathematics
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log8 is just a number so 3-log8 = 3logx or logx = (3-log8)/3 try it from there...
a = 10^3 and not 103. 3 - log 8 = 3 * log x We know that 3 = log 10^3 So log 10^3 - log 8 = log 10^3 * log x Log rules tell us that log p - log q = log (p/q) Thus the resulting equation is log (10^3 / 8) = log 10^3 * log x Can you figure out the solution from here? :)
I thinkkk so, thank you so much !

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Other answers:

\[3=\log 8++\log x^3=\log (8x^3),8x^3=10^3,(2x)^3=10^3\]
2x=10 x=?

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