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 11 months ago
Can someone pleassssse help me with this problem? :)
Solve for x. Enter only a number.
3 = log8 + 3logx
HINT: If loga = 3, then a = 103.
 11 months ago
Can someone pleassssse help me with this problem? :) Solve for x. Enter only a number. 3 = log8 + 3logx HINT: If loga = 3, then a = 103.

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MrNood
 11 months ago
Best ResponseYou've already chosen the best response.0log8 is just a number so 3log8 = 3logx or logx = (3log8)/3 try it from there...

AkashdeepDeb
 11 months ago
Best ResponseYou've already chosen the best response.0a = 10^3 and not 103. 3  log 8 = 3 * log x We know that 3 = log 10^3 So log 10^3  log 8 = log 10^3 * log x Log rules tell us that log p  log q = log (p/q) Thus the resulting equation is log (10^3 / 8) = log 10^3 * log x Can you figure out the solution from here? :)

cayssaday
 11 months ago
Best ResponseYou've already chosen the best response.0I thinkkk so, thank you so much !

surjithayer
 11 months ago
Best ResponseYou've already chosen the best response.1\[3=\log 8++\log x^3=\log (8x^3),8x^3=10^3,(2x)^3=10^3\]
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