A community for students.
Here's the question you clicked on:
 0 viewing
Gabylovesyou
 one year ago
@johnweldon1993 @phi @karatechopper
Gabylovesyou
 one year ago
@johnweldon1993 @phi @karatechopper

This Question is Closed

Gabylovesyou
 one year ago
Best ResponseYou've already chosen the best response.1Look at the right triangle ABC. Right triangle ABC has a right angle at B. Segment BD meets segment AC at a right angle. A student made the following chart to prove that AB2 + BC2 = AC2. Statement Justification 1. Triangle ABC is similar to triangle BDC 1. Angle ABC = Angle BDC and Angle BCA = Angle DCB 2. BC2 = AC x DC 2. BC ÷ DC = BC ÷ AC because triangle ABC is similar to triangle BDC 3. Triangle ABC is similar to triangle ABD 3. Angle ABC = Angle ADB and Angle BAC = Angle DAB 4. AB2 = AC x AD 4. AB ÷ AD = AC ÷ AB because triangle ABC is similar to triangle ADB 5. AB2 + BC2 = AC x AD + AC x D = AC (AD + DC) 5. Adding Statement 1 and Statement 2 6. AB2 + BC2 = AC2 6. AD + DC = AC What is the flaw in the student's proof? Justification 3 should be "Angle ABC = Angle BAD and Angle BAC = Angle ABD." Justification 4 should be "AB ÷ AD = AB ÷ AC because triangle ABC is similar to triangle ABD." Justification 2 should be "BC ÷ DC = AC ÷ BC because triangle ABC is similar to triangle BDC." Justification 1 should be "Angle ABC = Angle BCD and Angle BCA = Angle DBC.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.