anonymous
  • anonymous
The minimum number of cards to be dealt from an arbitrary shuffled deck of 52 cards to guarantee that 3 cards are from the same suit are?
Mathematics
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anonymous
  • anonymous
The minimum number of cards to be dealt from an arbitrary shuffled deck of 52 cards to guarantee that 3 cards are from the same suit are?
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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AkashdeepDeb
  • AkashdeepDeb
Here they want us to calculate the possible combinations of getting 3 cards from the same suit. 1 suit has 13 cards. So you want to select 3 cards from any set of the 4 sets (hearts, clubs, spades, diamonds) containing 13 cards each. As you have to make a selection of 3 cards from 13 cards. The answer would be, \[{^{13}C_3}\]
AkashdeepDeb
  • AkashdeepDeb
Actually, my bad! As there are 4 such suits, there is a possibility that you may get it from either of the 4 sets of 13 cards. So the final answer would actually be: \[^{13}C_3 + ^{13}C_3 + ^{13}C_3 + ^{13}C_3 ~~or~~ 4 * ^{13}C_3\] Getting this? :)
anonymous
  • anonymous
what i can see is So the final answer would actually be: \[^{13}C_3 + ^{13}C_3 + ^{13}C_3 + ^{13}C_3 ~~or~~ 4 * ^{13}C_3\]

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anonymous
  • anonymous
i think it's not showing up the correct format of wht u wanna convey here !
AkashdeepDeb
  • AkashdeepDeb
There must be a problem with the website now. I am not being able to copy and paste anything here too. Let me message you the answer, hold on.
anonymous
  • anonymous
thank you :)
ganeshie8
  • ganeshie8
best case 3, worst case 9 so answer should be 9
AkashdeepDeb
  • AkashdeepDeb
Yeah, I corrected that for @moli1993 thanks, @ganeshie8 ! :D

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