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mathmale
 9 months ago
Best ResponseYou've already chosen the best response.1An important rule of logarithms is this : ln a  ln b = ln (a/b). Given that, what is ln 2  ln (3x+2)?

mathmale
 9 months ago
Best ResponseYou've already chosen the best response.1good. Now, \[\ln \frac{ 2 }{ 3x+2 }=1.\] how would you now get rid of the ln operator? We want to solve this equation for x.

Megaforte8600
 9 months ago
Best ResponseYou've already chosen the best response.0e^ln ( 2/ 3x + 2 ) = e^1

mathmale
 9 months ago
Best ResponseYou've already chosen the best response.1Hey, that's really cool. Can you now simplify this equation?

mathmale
 9 months ago
Best ResponseYou've already chosen the best response.1Use the fact that e^(ln a) = a. If this is true (which it is), then what is \[e ^{\ln \frac{ 2 }{ 3x+2 }}?\]

mathmale
 9 months ago
Best ResponseYou've already chosen the best response.1The right side is simply e^1, or e.

Megaforte8600
 9 months ago
Best ResponseYou've already chosen the best response.0ok, so its now (2/3x + 2) = 1

mathmale
 9 months ago
Best ResponseYou've already chosen the best response.1Other than that your 3x+1 should be within parentheses, yes! Mind rewriting that? Don't need parenthesis in front of the first 2.

mathmale
 9 months ago
Best ResponseYou've already chosen the best response.1Yes, or \[\frac{ 3x+2 }{ 2 }=\frac{ 1 }{ e }\] One way of solving this would be to crossmultiply. We have to isolate x on the left side of the equation. I need to log off now, but think you're well on the way to solving this problem properly. See you again soon, I hope.

Megaforte8600
 9 months ago
Best ResponseYou've already chosen the best response.0im still confused

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1are you confused on the cross multiplication part? he means if you have \[\frac{a}{b}=\frac{c}{d} \text{ you can do } ad=cb\]

myininaya
 9 months ago
Best ResponseYou've already chosen the best response.1and remember we are solving for x remember treat e like you would treat 2 or 3 or any other constant number
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