Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

wayne2434

  • 2 years ago

Weights of male mountain lions follow the normal distribution with a median of 150 pounds and an interquartile range of 8.2 pounds. Find the 75th percentile of the weights.

  • This Question is Open
  1. kirbykirby
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    In a normal distribution, the median = mean. Also, The mean = 50th percentile ("Q2") The interquartile range = Q3 - Q1 = 75th percentile - 25th percentile. Now, since the normal distribution is symmetric, half your data is below the mean, and half is above the mean. So, you proportionately find 8.2/2 = 4.1 pounds being Q3 - Q2 , and Q2 - Q1 Schematically: |dw:1397373422765:dw|

  2. kirbykirby
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thus I hope you can see that Q3, the 75th percentile, is 150+4.1 = 154.1

  3. kirbykirby
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Maybe this picture is more clear: http://en.wikipedia.org/wiki/File:Boxplot_vs_PDF.svg

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy