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anonymous
 2 years ago
N2O5 is completely decomposed on heating. if 2 moles of N2O5 are decomposed then vol of O2 produced at R.T.P will be :
a. 2 x 24 litres
b. 5 x 22.4 litres
c. 4 x 24 litres
d. 5 x 24 litres
explain clearly i want conceptual understanding plz
anonymous
 2 years ago
N2O5 is completely decomposed on heating. if 2 moles of N2O5 are decomposed then vol of O2 produced at R.T.P will be : a. 2 x 24 litres b. 5 x 22.4 litres c. 4 x 24 litres d. 5 x 24 litres explain clearly i want conceptual understanding plz

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AkashdeepDeb
 2 years ago
Best ResponseYou've already chosen the best response.0It depends on HOW it decomposes. The decomposition of \(N_2O_5\) takes place as so: N2O5(g) > 2NO2(g) + 1/2 O2(g) Thus 2 moles of N2O5, decomposed would form, 2N2O5 > 4NO2 + O2 Thus, 2 moles of N2O5 forms 1 mole O2 Thus, as 1 mole of O2 at RTP has volume of 24 liters, the answer must be 24 liters.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0there is no answer as 24 liters in options ..
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