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bintemazhar
 11 months ago
N2O5 is completely decomposed on heating. if 2 moles of N2O5 are decomposed then vol of O2 produced at R.T.P will be :
a. 2 x 24 litres
b. 5 x 22.4 litres
c. 4 x 24 litres
d. 5 x 24 litres
explain clearly i want conceptual understanding plz
bintemazhar
 11 months ago
N2O5 is completely decomposed on heating. if 2 moles of N2O5 are decomposed then vol of O2 produced at R.T.P will be : a. 2 x 24 litres b. 5 x 22.4 litres c. 4 x 24 litres d. 5 x 24 litres explain clearly i want conceptual understanding plz

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AkashdeepDeb
 11 months ago
Best ResponseYou've already chosen the best response.0It depends on HOW it decomposes. The decomposition of \(N_2O_5\) takes place as so: N2O5(g) > 2NO2(g) + 1/2 O2(g) Thus 2 moles of N2O5, decomposed would form, 2N2O5 > 4NO2 + O2 Thus, 2 moles of N2O5 forms 1 mole O2 Thus, as 1 mole of O2 at RTP has volume of 24 liters, the answer must be 24 liters.

bintemazhar
 11 months ago
Best ResponseYou've already chosen the best response.0there is no answer as 24 liters in options ..
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