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ravend20 Group Title

I = 4000 x ( 9 + 1)/100 x 3

  • 7 months ago
  • 7 months ago

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  1. Baseball_King Group Title
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    I= 120

    • 7 months ago
  2. mathstudent55 Group Title
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    Is this the problem? \(I = 4000 \times \dfrac{9 + 1}{100} \times 3\)

    • 7 months ago
  3. mathstudent55 Group Title
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    This is what you wrote above, so I'll help you with it. \(I = 4000 \times \dfrac{9 + 1}{100} \times 3\) First, you must do the addition in the numerator. \(I = 4000 \times \dfrac{10}{100} \times 3\) Now do the division in the fraction. \(I = 4000 \times 0.1 \times 3\) Now multiply the three numbers together. \(I = 1200\)

    • 7 months ago
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