## ravend20 Group Title I = 4000 x ( 9 + 1)/100 x 3 7 months ago 7 months ago

1. Baseball_King

I= 120

2. mathstudent55

Is this the problem? $$I = 4000 \times \dfrac{9 + 1}{100} \times 3$$

3. mathstudent55

This is what you wrote above, so I'll help you with it. $$I = 4000 \times \dfrac{9 + 1}{100} \times 3$$ First, you must do the addition in the numerator. $$I = 4000 \times \dfrac{10}{100} \times 3$$ Now do the division in the fraction. $$I = 4000 \times 0.1 \times 3$$ Now multiply the three numbers together. $$I = 1200$$