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Baseball_King Group TitleBest ResponseYou've already chosen the best response.0
I= 120
 8 months ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
Is this the problem? \(I = 4000 \times \dfrac{9 + 1}{100} \times 3\)
 8 months ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
This is what you wrote above, so I'll help you with it. \(I = 4000 \times \dfrac{9 + 1}{100} \times 3\) First, you must do the addition in the numerator. \(I = 4000 \times \dfrac{10}{100} \times 3\) Now do the division in the fraction. \(I = 4000 \times 0.1 \times 3\) Now multiply the three numbers together. \(I = 1200\)
 8 months ago
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