anonymous
  • anonymous
lol
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
add both equations
anonymous
  • anonymous
you'll get 2x = 22
anonymous
  • anonymous
solve for that, and you'll get 11

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anonymous
  • anonymous
I though that too, but that's not an answer. :(
anonymous
  • anonymous
thought*
anonymous
  • anonymous
what are the options?
anonymous
  • anonymous
-22 -12 -2
anonymous
  • anonymous
I have to go, I'll respond to this in a little bit. Sorry.
tkhunny
  • tkhunny
x + y = 12 x - y = 10 D = (1)(-1)-(1)(1) Dx = (12)(-1)-(10)(1) Dy = (1)(10)-(1)(12)
anonymous
  • anonymous
That's fine. Thanks though :)
anonymous
  • anonymous
Are you saying it's -22? It's asking for the x determinant if you're wondering. I just want to be able to solve the future ones. :)
mathmale
  • mathmale
@ambeeeerlw : Determinants are not used much any longer. However, you're apparently expected to know how to apply determinants to solving systems of linear equations. Have you tried looking up "determinants" on the 'Net? If you want to learn how do use determinants, either @tkhunny or I would be happy to help you ... but we do not give out just answers.
anonymous
  • anonymous
I actually wasn't expecting just answers, I was double checking his work so I'd know how to future problems. I'm not trying to just collect answers, I swear. I have looked it up, but I can;t a way that explains it well enough where I fully understand. :( Can you help me?
anonymous
  • anonymous
( or her work, I didn't see who it was)
tkhunny
  • tkhunny
"Cramer's Rule" is very interesting. It just works. It leans toward what we like to call an "Existence" result. This means it may or may not be very useful in the real world, but it demonstrates that (or under what conditions) the solution exists. Good thing to know.
anonymous
  • anonymous
My teacher didn't even mention it is "Cramer's Rule," so that's a nice factor to know.. I do online school, and I can't really get it touch with my teacher, reasoning behind me getting help from her.
mathmale
  • mathmale
@tkhunny typed this out for you earlier: x + y = 12 x - y = 10 D = (1)(-1)-(1)(1) Dx = (12)(-1)-(10)(1) Dy = (1)(10)-(1)(12) First, he found the "system determinant." He realized that x + y = 12 x - y = 10 can be re-written as 1x+1y=12 1x-1y=10 which we need to do because we need those coefficients of x and y. Notice how the coefficients (alone) are 1 1 1 -1 tkhunny now finds the "system determinant."|dw:1396529907980:dw|
mathmale
  • mathmale
The result is -1 -1, or -2. The system determinant is -2. Note that this is exactly the result obtained by tkhunny earlier. Have you seen this kind of work done before?
anonymous
  • anonymous
Yes, that is the only one have and that I understand.
mathmale
  • mathmale
Good. Now we need to find x. We take the system determinant, toss out the first column, and replace it with the constants (12 and 10):|dw:1396530274277:dw|
anonymous
  • anonymous
the products of those would be -12 and -10, right?
mathmale
  • mathmale
Right, and that adds up to -22. Thus, your x is found in this manner:|dw:1396530623039:dw|
anonymous
  • anonymous
10?
mathmale
  • mathmale
close. Try again.
mathmale
  • mathmale
and your y value is
anonymous
  • anonymous
I meant 11, oops :p
anonymous
  • anonymous
y value is 1? I think
mathmale
  • mathmale
|dw:1396530712310:dw|
mathmale
  • mathmale
Cool. Yes, y=1. Solution is (11,1). congrats!
anonymous
  • anonymous
I don't understand because the answers are only -22,-12, and -2. This is what confuses me
anonymous
  • anonymous
Is it asking for another part of the question? I'm unsure.
mathmale
  • mathmale
@tkhunny's "answers" are intermediate results. He gave you D=-2, Dx = -22 and Dy = -2.|dw:1396531164233:dw|
mathmale
  • mathmale
that's right!! they are both modifications of the system determinant.
mathmale
  • mathmale
And nothing to apologize for! I so much appreciate your sticking with this until completion. Hope to get to work with you again.
mathmale
  • mathmale
That's like music to the ears! :)

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