for the process of H2O (g) --> H2O (l) a) ΔH is negative and ΔS is negative. b) ΔH is negative and ΔS is positive. c) ΔH is positive and ΔS is positive d) ΔH is positive and ΔS is negative.

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for the process of H2O (g) --> H2O (l) a) ΔH is negative and ΔS is negative. b) ΔH is negative and ΔS is positive. c) ΔH is positive and ΔS is positive d) ΔH is positive and ΔS is negative.

Thermodynamics
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ok, I know the entropy will be negative because you are going from a gas to a liquid, so decreasing entropy. but what about the enthalpy ?
Because water vapour condenses, it gives away heat, so Process is exothermic. That is way delta H is negative. Because delta S = delta H/ T, it is also negative
thanks!

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